let i, k, j be Element of NAT ; for G being Go-board st i + k < len G & 1 <= j & j < width G & cell G,i,j meets cell G,(i + k),j holds
k <= 1
let G be Go-board; ( i + k < len G & 1 <= j & j < width G & cell G,i,j meets cell G,(i + k),j implies k <= 1 )
assume that
A1:
i + k < len G
and
A2:
1 <= j
and
A3:
j < width G
and
A4:
cell G,i,j meets cell G,(i + k),j
and
A5:
k > 1
; contradiction
(cell G,i,j) /\ (cell G,(i + k),j) <> {}
by A4, XBOOLE_0:def 7;
then consider p being Point of (TOP-REAL 2) such that
A6:
p in (cell G,i,j) /\ (cell G,(i + k),j)
by SUBSET_1:10;
A7:
p in cell G,i,j
by A6, XBOOLE_0:def 4;
A8:
p in cell G,(i + k),j
by A6, XBOOLE_0:def 4;
i + k >= 1
by A5, NAT_1:12;
then
cell G,(i + k),j = { |[r9,s9]| where r9, s9 is Real : ( (G * (i + k),1) `1 <= r9 & r9 <= (G * ((i + k) + 1),1) `1 & (G * 1,j) `2 <= s9 & s9 <= (G * 1,(j + 1)) `2 ) }
by A1, A2, A3, GOBRD11:32;
then consider r9, s9 being Real such that
A9:
p = |[r9,s9]|
and
A10:
(G * (i + k),1) `1 <= r9
and
r9 <= (G * ((i + k) + 1),1) `1
and
(G * 1,j) `2 <= s9
and
s9 <= (G * 1,(j + 1)) `2
by A8;
A11:
1 < width G
by A2, A3, XXREAL_0:2;
( i = 0 or i > 0 )
by NAT_1:3;
then A12:
( i = 0 or i >= 1 + 0 )
by NAT_1:9;
per cases
( i = 0 or i >= 1 )
by A12;
suppose A13:
i = 0
;
contradictionthen
cell G,
i,
j = { |[r,s]| where r, s is Real : ( r <= (G * 1,1) `1 & (G * 1,j) `2 <= s & s <= (G * 1,(j + 1)) `2 ) }
by A2, A3, GOBRD11:26;
then consider r,
s being
Real such that A14:
p = |[r,s]|
and A15:
r <= (G * 1,1) `1
and
(G * 1,j) `2 <= s
and
s <= (G * 1,(j + 1)) `2
by A7;
A16:
k <= len G
by A1, NAT_1:12;
A17:
p `1 = r
by A14, EUCLID:56;
p `1 = r9
by A9, EUCLID:56;
then
(G * k,1) `1 <= (G * 1,1) `1
by A10, A13, A15, A17, XXREAL_0:2;
hence
contradiction
by A5, A11, A16, GOBOARD5:4;
verum end; suppose A18:
i >= 1
;
contradiction
i < len G
by A1, NAT_1:12;
then
cell G,
i,
j = { |[r,s]| where r, s is Real : ( (G * i,1) `1 <= r & r <= (G * (i + 1),1) `1 & (G * 1,j) `2 <= s & s <= (G * 1,(j + 1)) `2 ) }
by A2, A3, A18, GOBRD11:32;
then consider r,
s being
Real such that A19:
p = |[r,s]|
and
(G * i,1) `1 <= r
and A20:
r <= (G * (i + 1),1) `1
and
(G * 1,j) `2 <= s
and
s <= (G * 1,(j + 1)) `2
by A7;
A21:
1
<= i + 1
by NAT_1:12;
A22:
i + 1
< k + i
by A5, XREAL_1:8;
A23:
p `1 = r
by A19, EUCLID:56;
p `1 = r9
by A9, EUCLID:56;
then
(G * (i + k),1) `1 <= (G * (i + 1),1) `1
by A10, A20, A23, XXREAL_0:2;
hence
contradiction
by A1, A11, A21, A22, GOBOARD5:4;
verum end; end;