let A be closed-interval Subset of REAL ; ( A = [.0 ,1.] implies integral sinh ,A = ((number_e - 1) ^2 ) / (2 * number_e ) )
exp_R 1 > 0
by SIN_COS:60;
then A1:
2 * number_e > 0
by IRRAT_1:def 7, XREAL_1:131;
assume
A = [.0 ,1.]
; integral sinh ,A = ((number_e - 1) ^2 ) / (2 * number_e )
then
( upper_bound A = 1 & lower_bound A = 0 )
by Th37;
then integral sinh ,A =
(((number_e ^2 ) + 1) / (2 * number_e )) - 1
by Th18, Th19, Th55
.=
(((number_e ^2 ) + 1) / (2 * number_e )) - ((2 * number_e ) / (2 * number_e ))
by A1, XCMPLX_1:60
.=
(((number_e ^2 ) + 1) - (2 * number_e )) / (2 * number_e )
by XCMPLX_1:121
.=
(((number_e ^2 ) - ((2 * number_e ) * 1)) + (1 ^2 )) / (2 * number_e )
.=
((number_e - 1) ^2 ) / (2 * number_e )
;
hence
integral sinh ,A = ((number_e - 1) ^2 ) / (2 * number_e )
; verum