let A be closed-interval Subset of REAL ; for f being PartFunc of REAL ,REAL
for Z being open Subset of REAL st A c= Z & ( for x being Real st x in Z holds
f . x = (sin . (sin . x)) * (cos . x) ) & Z = dom f & f | A is continuous holds
integral f,A = ((- (cos * sin )) . (upper_bound A)) - ((- (cos * sin )) . (lower_bound A))
let f be PartFunc of REAL ,REAL ; for Z being open Subset of REAL st A c= Z & ( for x being Real st x in Z holds
f . x = (sin . (sin . x)) * (cos . x) ) & Z = dom f & f | A is continuous holds
integral f,A = ((- (cos * sin )) . (upper_bound A)) - ((- (cos * sin )) . (lower_bound A))
let Z be open Subset of REAL ; ( A c= Z & ( for x being Real st x in Z holds
f . x = (sin . (sin . x)) * (cos . x) ) & Z = dom f & f | A is continuous implies integral f,A = ((- (cos * sin )) . (upper_bound A)) - ((- (cos * sin )) . (lower_bound A)) )
assume A1:
( A c= Z & ( for x being Real st x in Z holds
f . x = (sin . (sin . x)) * (cos . x) ) & Z = dom f & f | A is continuous )
; integral f,A = ((- (cos * sin )) . (upper_bound A)) - ((- (cos * sin )) . (lower_bound A))
then A2:
( f is_integrable_on A & f | A is bounded )
by INTEGRA5:10, INTEGRA5:11;
B1:
dom sin = REAL
by SIN_COS:27;
( rng sin c= dom sin & dom sin = dom cos )
by SIN_COS:27;
then
dom (cos * sin ) = REAL
by B1, RELAT_1:46;
then B2:
dom (- (cos * sin )) = REAL
by VALUED_1:8;
A4:
cos * sin is_differentiable_on Z
by FDIFF_10:9;
then A5:
(- 1) (#) (cos * sin ) is_differentiable_on Z
by B2, FDIFF_1:28, A;
A6:
for x being Real st x in Z holds
((- (cos * sin )) `| Z) . x = (sin . (sin . x)) * (cos . x)
A8:
for x being Real st x in dom ((- (cos * sin )) `| Z) holds
((- (cos * sin )) `| Z) . x = f . x
dom ((- (cos * sin )) `| Z) = dom f
by A1, A5, FDIFF_1:def 8;
then
(- (cos * sin )) `| Z = f
by A8, PARTFUN1:34;
hence
integral f,A = ((- (cos * sin )) . (upper_bound A)) - ((- (cos * sin )) . (lower_bound A))
by A1, A2, A5, INTEGRA5:13; verum