let A be closed-interval Subset of REAL ; for f being PartFunc of REAL ,REAL
for Z being open Subset of REAL st A c= Z & ( for x being Real st x in Z holds
f . x = (cos . (cos . x)) * (sin . x) ) & Z = dom f & f | A is continuous holds
integral f,A = ((- (sin * cos )) . (upper_bound A)) - ((- (sin * cos )) . (lower_bound A))
let f be PartFunc of REAL ,REAL ; for Z being open Subset of REAL st A c= Z & ( for x being Real st x in Z holds
f . x = (cos . (cos . x)) * (sin . x) ) & Z = dom f & f | A is continuous holds
integral f,A = ((- (sin * cos )) . (upper_bound A)) - ((- (sin * cos )) . (lower_bound A))
let Z be open Subset of REAL ; ( A c= Z & ( for x being Real st x in Z holds
f . x = (cos . (cos . x)) * (sin . x) ) & Z = dom f & f | A is continuous implies integral f,A = ((- (sin * cos )) . (upper_bound A)) - ((- (sin * cos )) . (lower_bound A)) )
assume A1:
( A c= Z & ( for x being Real st x in Z holds
f . x = (cos . (cos . x)) * (sin . x) ) & Z = dom f & f | A is continuous )
; integral f,A = ((- (sin * cos )) . (upper_bound A)) - ((- (sin * cos )) . (lower_bound A))
then A2:
( f is_integrable_on A & f | A is bounded )
by INTEGRA5:10, INTEGRA5:11;
( dom cos = REAL & rng cos c= dom cos & dom sin = dom cos )
by SIN_COS:27;
then
dom (sin * cos ) = REAL
by RELAT_1:46;
then B:
dom (- (sin * cos )) = REAL
by VALUED_1:8;
A4:
sin * cos is_differentiable_on Z
by FDIFF_10:8;
then A5:
(- 1) (#) (sin * cos ) is_differentiable_on Z
by B, FDIFF_1:28, A;
A6:
for x being Real st x in Z holds
((- (sin * cos )) `| Z) . x = (cos . (cos . x)) * (sin . x)
A8:
for x being Real st x in dom ((- (sin * cos )) `| Z) holds
((- (sin * cos )) `| Z) . x = f . x
dom ((- (sin * cos )) `| Z) = dom f
by A1, A5, FDIFF_1:def 8;
then
(- (sin * cos )) `| Z = f
by A8, PARTFUN1:34;
hence
integral f,A = ((- (sin * cos )) . (upper_bound A)) - ((- (sin * cos )) . (lower_bound A))
by A1, A2, A5, INTEGRA5:13; verum