let A be closed-interval Subset of REAL ; for f being PartFunc of REAL ,REAL
for Z being open Subset of REAL st A c= Z & ( for x being Real st x in Z holds
f . x = ((exp_R . x) * (cos . (exp_R . x))) / ((sin . (exp_R . x)) ^2 ) ) & Z c= dom (cosec * exp_R ) & Z = dom f & f | A is continuous holds
integral f,A = ((- (cosec * exp_R )) . (upper_bound A)) - ((- (cosec * exp_R )) . (lower_bound A))
let f be PartFunc of REAL ,REAL ; for Z being open Subset of REAL st A c= Z & ( for x being Real st x in Z holds
f . x = ((exp_R . x) * (cos . (exp_R . x))) / ((sin . (exp_R . x)) ^2 ) ) & Z c= dom (cosec * exp_R ) & Z = dom f & f | A is continuous holds
integral f,A = ((- (cosec * exp_R )) . (upper_bound A)) - ((- (cosec * exp_R )) . (lower_bound A))
let Z be open Subset of REAL ; ( A c= Z & ( for x being Real st x in Z holds
f . x = ((exp_R . x) * (cos . (exp_R . x))) / ((sin . (exp_R . x)) ^2 ) ) & Z c= dom (cosec * exp_R ) & Z = dom f & f | A is continuous implies integral f,A = ((- (cosec * exp_R )) . (upper_bound A)) - ((- (cosec * exp_R )) . (lower_bound A)) )
assume A1:
( A c= Z & ( for x being Real st x in Z holds
f . x = ((exp_R . x) * (cos . (exp_R . x))) / ((sin . (exp_R . x)) ^2 ) ) & Z c= dom (cosec * exp_R ) & Z = dom f & f | A is continuous )
; integral f,A = ((- (cosec * exp_R )) . (upper_bound A)) - ((- (cosec * exp_R )) . (lower_bound A))
then A2:
( f is_integrable_on A & f | A is bounded )
by INTEGRA5:10, INTEGRA5:11;
A3:
- (cosec * exp_R ) is_differentiable_on Z
by A1, Th2;
A4:
for x being Real st x in dom ((- (cosec * exp_R )) `| Z) holds
((- (cosec * exp_R )) `| Z) . x = f . x
dom ((- (cosec * exp_R )) `| Z) = dom f
by A1, A3, FDIFF_1:def 8;
then
(- (cosec * exp_R )) `| Z = f
by A4, PARTFUN1:34;
hence
integral f,A = ((- (cosec * exp_R )) . (upper_bound A)) - ((- (cosec * exp_R )) . (lower_bound A))
by A1, A2, A3, INTEGRA5:13; verum