let A be closed-interval Subset of REAL ; for f, f1 being PartFunc of REAL ,REAL
for Z being open Subset of REAL st A c= Z & Z c= ].(- 1),1.[ & f = (exp_R * arctan ) / (f1 + (#Z 2)) & ( for x being Real st x in Z holds
f1 . x = 1 ) & Z = dom f & f | A is continuous holds
integral f,A = ((exp_R * arctan ) . (upper_bound A)) - ((exp_R * arctan ) . (lower_bound A))
let f, f1 be PartFunc of REAL ,REAL ; for Z being open Subset of REAL st A c= Z & Z c= ].(- 1),1.[ & f = (exp_R * arctan ) / (f1 + (#Z 2)) & ( for x being Real st x in Z holds
f1 . x = 1 ) & Z = dom f & f | A is continuous holds
integral f,A = ((exp_R * arctan ) . (upper_bound A)) - ((exp_R * arctan ) . (lower_bound A))
let Z be open Subset of REAL ; ( A c= Z & Z c= ].(- 1),1.[ & f = (exp_R * arctan ) / (f1 + (#Z 2)) & ( for x being Real st x in Z holds
f1 . x = 1 ) & Z = dom f & f | A is continuous implies integral f,A = ((exp_R * arctan ) . (upper_bound A)) - ((exp_R * arctan ) . (lower_bound A)) )
assume A1:
( A c= Z & Z c= ].(- 1),1.[ & f = (exp_R * arctan ) / (f1 + (#Z 2)) & ( for x being Real st x in Z holds
f1 . x = 1 ) & Z = dom f & f | A is continuous )
; integral f,A = ((exp_R * arctan ) . (upper_bound A)) - ((exp_R * arctan ) . (lower_bound A))
then A2:
( f is_integrable_on A & f | A is bounded )
by INTEGRA5:10, INTEGRA5:11;
Z = (dom (exp_R * arctan )) /\ ((dom (f1 + (#Z 2))) \ ((f1 + (#Z 2)) " {0 }))
by RFUNCT_1:def 4, A1;
then A3:
( Z c= dom (exp_R * arctan ) & Z c= (dom (f1 + (#Z 2))) \ ((f1 + (#Z 2)) " {0 }) )
by XBOOLE_1:18;
then A4:
Z c= dom ((f1 + (#Z 2)) ^ )
by RFUNCT_1:def 8;
dom ((f1 + (#Z 2)) ^ ) c= dom (f1 + (#Z 2))
by RFUNCT_1:11;
then A5:
Z c= dom (f1 + (#Z 2))
by XBOOLE_1:1, A4;
A6:
exp_R * arctan is_differentiable_on Z
by A1, A3, SIN_COS9:119;
B:
for x being Real st x in Z holds
f . x = (exp_R . (arctan . x)) / (1 + (x ^2 ))
A8:
for x being Real st x in dom ((exp_R * arctan ) `| Z) holds
((exp_R * arctan ) `| Z) . x = f . x
dom ((exp_R * arctan ) `| Z) = dom f
by A1, A6, FDIFF_1:def 8;
then
(exp_R * arctan ) `| Z = f
by A8, PARTFUN1:34;
hence
integral f,A = ((exp_R * arctan ) . (upper_bound A)) - ((exp_R * arctan ) . (lower_bound A))
by A1, A2, A3, SIN_COS9:119, INTEGRA5:13; verum