let A be closed-interval Subset of REAL ; for f1, f being PartFunc of REAL ,REAL
for Z being open Subset of REAL st A c= Z & ( for x being Real st x in Z holds
( f1 . x = 1 & arctan . x > 0 ) ) & f = ((f1 + (#Z 2)) (#) arctan ) ^ & Z c= ].(- 1),1.[ & Z c= dom (ln * arctan ) & Z = dom f & f | A is continuous holds
integral f,A = ((ln * arctan ) . (upper_bound A)) - ((ln * arctan ) . (lower_bound A))
let f1, f be PartFunc of REAL ,REAL ; for Z being open Subset of REAL st A c= Z & ( for x being Real st x in Z holds
( f1 . x = 1 & arctan . x > 0 ) ) & f = ((f1 + (#Z 2)) (#) arctan ) ^ & Z c= ].(- 1),1.[ & Z c= dom (ln * arctan ) & Z = dom f & f | A is continuous holds
integral f,A = ((ln * arctan ) . (upper_bound A)) - ((ln * arctan ) . (lower_bound A))
let Z be open Subset of REAL ; ( A c= Z & ( for x being Real st x in Z holds
( f1 . x = 1 & arctan . x > 0 ) ) & f = ((f1 + (#Z 2)) (#) arctan ) ^ & Z c= ].(- 1),1.[ & Z c= dom (ln * arctan ) & Z = dom f & f | A is continuous implies integral f,A = ((ln * arctan ) . (upper_bound A)) - ((ln * arctan ) . (lower_bound A)) )
assume A1:
( A c= Z & ( for x being Real st x in Z holds
( f1 . x = 1 & arctan . x > 0 ) ) & f = ((f1 + (#Z 2)) (#) arctan ) ^ & Z c= ].(- 1),1.[ & Z c= dom (ln * arctan ) & Z = dom f & f | A is continuous )
; integral f,A = ((ln * arctan ) . (upper_bound A)) - ((ln * arctan ) . (lower_bound A))
then A2:
( f is_integrable_on A & f | A is bounded )
by INTEGRA5:10, INTEGRA5:11;
A3:
for x being Real st x in Z holds
arctan . x > 0
by A1;
then A4:
ln * arctan is_differentiable_on Z
by A1, SIN_COS9:89;
Z c= dom ((f1 + (#Z 2)) (#) arctan )
by RFUNCT_1:11, A1;
then
Z c= (dom (f1 + (#Z 2))) /\ (dom arctan )
by VALUED_1:def 4;
then A5:
Z c= dom (f1 + (#Z 2))
by XBOOLE_1:18;
B:
for x being Real st x in Z holds
f . x = 1 / ((1 + (x ^2 )) * (arctan . x))
A6:
for x being Real st x in dom ((ln * arctan ) `| Z) holds
((ln * arctan ) `| Z) . x = f . x
dom ((ln * arctan ) `| Z) = dom f
by A1, A4, FDIFF_1:def 8;
then
(ln * arctan ) `| Z = f
by A6, PARTFUN1:34;
hence
integral f,A = ((ln * arctan ) . (upper_bound A)) - ((ln * arctan ) . (lower_bound A))
by A1, A2, A4, INTEGRA5:13; verum