let f be Polynomial of F_Complex ; (f *' ) *' = f
set g = (f *' ) *' ;
A1:
now let k9 be
set ;
( k9 in dom ((f *' ) *' ) implies ((f *' ) *' ) . k9 = f . k9 )assume
k9 in dom ((f *' ) *' )
;
((f *' ) *' ) . k9 = f . k9then reconsider k =
k9 as
Element of
NAT ;
((f *' ) *' ) . k =
((power F_Complex ) . (- (1_ F_Complex )),k) * (((f *' ) . k) *' )
by Def9
.=
((power F_Complex ) . (- (1_ F_Complex )),k) * ((((power F_Complex ) . (- (1_ F_Complex )),k) * ((f . k) *' )) *' )
by Def9
.=
((power F_Complex ) . (- (1_ F_Complex )),k) * ((((power F_Complex ) . (- (1_ F_Complex )),k) *' ) * (((f . k) *' ) *' ))
by COMPLFLD:90
.=
(((power F_Complex ) . (- (1_ F_Complex )),k) * (((power F_Complex ) . (- (1_ F_Complex )),k) *' )) * (f . k)
.=
(((power F_Complex ) . (- (1_ F_Complex )),k) * ((power F_Complex ) . ((- (1_ F_Complex )) *' ),k)) * (f . k)
by Th5
.=
(((power F_Complex ) . (- (1_ F_Complex )),k) * ((power F_Complex ) . (- (1_ F_Complex )),k)) * (f . k)
by Lm2, Lm3
.=
((power F_Complex ) . (- (1_ F_Complex )),(k + k)) * (f . k)
by Th3
.=
((power F_Complex ) . (- (1_ F_Complex )),(2 * k)) * (f . k)
.=
(1_ F_Complex ) * (f . k)
by Th4
;
hence
((f *' ) *' ) . k9 = f . k9
by VECTSP_1:def 19;
verum end;
dom ((f *' ) *' ) =
NAT
by FUNCT_2:def 1
.=
dom f
by FUNCT_2:def 1
;
hence
(f *' ) *' = f
by A1, FUNCT_1:9; verum