let p be FinSequence; for m being Element of NAT st m <= len p holds
(1,m -cut p) ^ ((m + 1),(len p) -cut p) = p
let m be Element of NAT ; ( m <= len p implies (1,m -cut p) ^ ((m + 1),(len p) -cut p) = p )
set cp1 = 1,m -cut p;
set cpm = (m + 1),(len p) -cut p;
A1:
0 + 1 = 1
;
assume
m <= len p
; (1,m -cut p) ^ ((m + 1),(len p) -cut p) = p
hence (1,m -cut p) ^ ((m + 1),(len p) -cut p) =
1,(len p) -cut p
by A1, Th8
.=
p
by Th7
;
verum