let i1, j1, j2 be Element of NAT ; for G1, G2 being Go-board st Values G1 c= Values G2 & [i1,j1] in Indices G1 & 1 <= j2 & j2 <= width G2 & G1 * i1,j1 = G2 * 1,j2 holds
i1 = 1
let G1, G2 be Go-board; ( Values G1 c= Values G2 & [i1,j1] in Indices G1 & 1 <= j2 & j2 <= width G2 & G1 * i1,j1 = G2 * 1,j2 implies i1 = 1 )
assume that
A1:
Values G1 c= Values G2
and
A2:
[i1,j1] in Indices G1
and
A3:
( 1 <= j2 & j2 <= width G2 )
and
A4:
G1 * i1,j1 = G2 * 1,j2
; i1 = 1
set p = G1 * 1,j1;
A5:
( 1 <= j1 & j1 <= width G1 )
by A2, MATRIX_1:39;
assume A6:
i1 <> 1
; contradiction
1 <= i1
by A2, MATRIX_1:39;
then A7:
1 < i1
by A6, XXREAL_0:1;
i1 <= len G1
by A2, MATRIX_1:39;
then A8:
(G1 * 1,j1) `1 < (G1 * i1,j1) `1
by A5, A7, GOBOARD5:4;
0 <> len G1
by GOBOARD1:def 5;
then
1 <= len G1
by NAT_1:14;
then
[1,j1] in Indices G1
by A5, MATRIX_1:37;
then
G1 * 1,j1 in { (G1 * i,j) where i, j is Element of NAT : [i,j] in Indices G1 }
;
then
G1 * 1,j1 in Values G1
by Th7;
then
G1 * 1,j1 in Values G2
by A1;
then
G1 * 1,j1 in { (G2 * i,j) where i, j is Element of NAT : [i,j] in Indices G2 }
by Th7;
then consider i, j being Element of NAT such that
A9:
G1 * 1,j1 = G2 * i,j
and
A10:
[i,j] in Indices G2
;
A11:
( 1 <= j & j <= width G2 )
by A10, MATRIX_1:39;
0 <> len G2
by GOBOARD1:def 5;
then A12:
1 <= len G2
by NAT_1:14;
then A13: (G2 * 1,j) `1 =
(G2 * 1,1) `1
by A11, GOBOARD5:3
.=
(G2 * 1,j2) `1
by A3, A12, GOBOARD5:3
;
A14:
i <= len G2
by A10, MATRIX_1:39;
1 <= i
by A10, MATRIX_1:39;
then
1 < i
by A4, A8, A9, A13, XXREAL_0:1;
hence
contradiction
by A4, A8, A9, A14, A11, A13, GOBOARD5:4; verum