let n1, n3, n2 be Element of NAT ; for S being Gene-Set
for p1, p2 being Individual of S holds
( crossover p1,p2,n1,n1,n3 = crossover p1,p2,n3 & crossover p1,p2,n1,n2,n1 = crossover p1,p2,n2 & crossover p1,p2,n1,n2,n2 = crossover p1,p2,n1 )
let S be Gene-Set; for p1, p2 being Individual of S holds
( crossover p1,p2,n1,n1,n3 = crossover p1,p2,n3 & crossover p1,p2,n1,n2,n1 = crossover p1,p2,n2 & crossover p1,p2,n1,n2,n2 = crossover p1,p2,n1 )
let p1, p2 be Individual of S; ( crossover p1,p2,n1,n1,n3 = crossover p1,p2,n3 & crossover p1,p2,n1,n2,n1 = crossover p1,p2,n2 & crossover p1,p2,n1,n2,n2 = crossover p1,p2,n1 )
crossover p1,p2,n1,n1,n3 = crossover p1,(crossover p2,p1,n1,n1),n3
by Th12;
hence
crossover p1,p2,n1,n1,n3 = crossover p1,p2,n3
by Th12; ( crossover p1,p2,n1,n2,n1 = crossover p1,p2,n2 & crossover p1,p2,n1,n2,n2 = crossover p1,p2,n1 )
crossover p1,p2,n1,n2,n1 =
crossover p1,p2,n1,n1,n2
by Th25
.=
crossover p1,(crossover p2,p1,n1,n1),n2
by Th12
;
hence
crossover p1,p2,n1,n2,n1 = crossover p1,p2,n2
by Th12; crossover p1,p2,n1,n2,n2 = crossover p1,p2,n1
thus crossover p1,p2,n1,n2,n2 =
crossover p1,p2,n2,n2,n1
by Th26
.=
crossover p1,(crossover p2,p1,n2,n2),n1
by Th12
.=
crossover p1,p2,n1
by Th12
; verum