let C1, C2, C3 be non empty set ; for f being RMembership_Func of C1,C2
for g being RMembership_Func of C2,C3 holds converse (f (#) g) = (converse g) (#) (converse f)
let f be RMembership_Func of C1,C2; for g being RMembership_Func of C2,C3 holds converse (f (#) g) = (converse g) (#) (converse f)
let g be RMembership_Func of C2,C3; converse (f (#) g) = (converse g) (#) (converse f)
A1:
dom ((converse g) (#) (converse f)) = [:C3,C1:]
by FUNCT_2:def 1;
A2:
for c being Element of [:C3,C1:] st c in [:C3,C1:] holds
(converse (f (#) g)) . c = ((converse g) (#) (converse f)) . c
proof
let c be
Element of
[:C3,C1:];
( c in [:C3,C1:] implies (converse (f (#) g)) . c = ((converse g) (#) (converse f)) . c )
assume
c in [:C3,C1:]
;
(converse (f (#) g)) . c = ((converse g) (#) (converse f)) . c
consider z,
x being
set such that A3:
z in C3
and A4:
x in C1
and A5:
c = [z,x]
by ZFMISC_1:def 2;
A6:
[x,z] in [:C1,C3:]
by A3, A4, ZFMISC_1:106;
A7:
((converse g) (#) (converse f)) . z,
x = upper_bound (rng (min (converse g),(converse f),z,x))
by A5, Def3;
(converse (f (#) g)) . z,
x =
(f (#) g) . x,
z
by A5, Def1
.=
upper_bound (rng (min f,g,x,z))
by A6, Def3
;
hence
(converse (f (#) g)) . c = ((converse g) (#) (converse f)) . c
by A3, A4, A5, A7, Lm5;
verum
end;
dom (converse (f (#) g)) = [:C3,C1:]
by FUNCT_2:def 1;
hence
converse (f (#) g) = (converse g) (#) (converse f)
by A1, A2, PARTFUN1:34; verum