let E be set ; for A being Subset of (E ^omega )
for m, n being Nat holds (A |^ m,n) ^^ A = A ^^ (A |^ m,n)
let A be Subset of (E ^omega ); for m, n being Nat holds (A |^ m,n) ^^ A = A ^^ (A |^ m,n)
let m, n be Nat; (A |^ m,n) ^^ A = A ^^ (A |^ m,n)
thus (A |^ m,n) ^^ A =
(A |^ m,n) ^^ (A |^ 1)
by FLANG_1:26
.=
(A |^ 1) ^^ (A |^ m,n)
by Th35
.=
A ^^ (A |^ m,n)
by FLANG_1:26
; verum