let Z be open Subset of REAL ; :: thesis: ( Z c= dom (sec * sin ) implies ( sec * sin is_differentiable_on Z & ( for x being Real st x in Z holds
((sec * sin ) `| Z) . x = ((cos . x) * (sin . (sin . x))) / ((cos . (sin . x)) ^2 ) ) ) )

assume A1: Z c= dom (sec * sin ) ; :: thesis: ( sec * sin is_differentiable_on Z & ( for x being Real st x in Z holds
((sec * sin ) `| Z) . x = ((cos . x) * (sin . (sin . x))) / ((cos . (sin . x)) ^2 ) ) )

A2: for x being Real st x in Z holds
cos . (sin . x) <> 0
proof
let x be Real; :: thesis: ( x in Z implies cos . (sin . x) <> 0 )
assume x in Z ; :: thesis: cos . (sin . x) <> 0
then sin . x in dom sec by A1, FUNCT_1:21;
hence cos . (sin . x) <> 0 by RFUNCT_1:13; :: thesis: verum
end;
A3: for x being Real st x in Z holds
sec * sin is_differentiable_in x
proof end;
then A4: sec * sin is_differentiable_on Z by A1, FDIFF_1:16;
for x being Real st x in Z holds
((sec * sin ) `| Z) . x = ((cos . x) * (sin . (sin . x))) / ((cos . (sin . x)) ^2 )
proof
let x be Real; :: thesis: ( x in Z implies ((sec * sin ) `| Z) . x = ((cos . x) * (sin . (sin . x))) / ((cos . (sin . x)) ^2 ) )
assume A5: x in Z ; :: thesis: ((sec * sin ) `| Z) . x = ((cos . x) * (sin . (sin . x))) / ((cos . (sin . x)) ^2 )
then A6: cos . (sin . x) <> 0 by A2;
then ( sin is_differentiable_in x & sec is_differentiable_in sin . x ) by Th1, SIN_COS:69;
then diff (sec * sin ),x = (diff sec ,(sin . x)) * (diff sin ,x) by FDIFF_2:13
.= ((sin . (sin . x)) / ((cos . (sin . x)) ^2 )) * (diff sin ,x) by A6, Th1
.= (cos . x) * ((sin . (sin . x)) / ((cos . (sin . x)) ^2 )) by SIN_COS:69 ;
hence ((sec * sin ) `| Z) . x = ((cos . x) * (sin . (sin . x))) / ((cos . (sin . x)) ^2 ) by A4, A5, FDIFF_1:def 8; :: thesis: verum
end;
hence ( sec * sin is_differentiable_on Z & ( for x being Real st x in Z holds
((sec * sin ) `| Z) . x = ((cos . x) * (sin . (sin . x))) / ((cos . (sin . x)) ^2 ) ) ) by A1, A3, FDIFF_1:16; :: thesis: verum