let Z be open Subset of REAL ; :: thesis: ( Z c= dom (tan * exp_R ) implies ( tan * exp_R is_differentiable_on Z & ( for x being Real st x in Z holds
((tan * exp_R ) `| Z) . x = (exp_R . x) / ((cos . (exp_R . x)) ^2 ) ) ) )

assume A1: Z c= dom (tan * exp_R ) ; :: thesis: ( tan * exp_R is_differentiable_on Z & ( for x being Real st x in Z holds
((tan * exp_R ) `| Z) . x = (exp_R . x) / ((cos . (exp_R . x)) ^2 ) ) )

A2: for x being Real st x in Z holds
cos . (exp_R . x) <> 0
proof
let x be Real; :: thesis: ( x in Z implies cos . (exp_R . x) <> 0 )
assume x in Z ; :: thesis: cos . (exp_R . x) <> 0
then exp_R . x in dom (sin / cos ) by A1, FUNCT_1:21;
hence cos . (exp_R . x) <> 0 by Th1; :: thesis: verum
end;
A3: for x being Real st x in Z holds
tan * exp_R is_differentiable_in x
proof end;
then A4: tan * exp_R is_differentiable_on Z by A1, FDIFF_1:16;
for x being Real st x in Z holds
((tan * exp_R ) `| Z) . x = (exp_R . x) / ((cos . (exp_R . x)) ^2 )
proof
let x be Real; :: thesis: ( x in Z implies ((tan * exp_R ) `| Z) . x = (exp_R . x) / ((cos . (exp_R . x)) ^2 ) )
assume A5: x in Z ; :: thesis: ((tan * exp_R ) `| Z) . x = (exp_R . x) / ((cos . (exp_R . x)) ^2 )
then A6: cos . (exp_R . x) <> 0 by A2;
then ( exp_R is_differentiable_in x & tan is_differentiable_in exp_R . x ) by FDIFF_7:46, SIN_COS:70;
then diff (tan * exp_R ),x = (diff tan ,(exp_R . x)) * (diff exp_R ,x) by FDIFF_2:13
.= (1 / ((cos . (exp_R . x)) ^2 )) * (diff exp_R ,x) by A6, FDIFF_7:46
.= (exp_R . x) / ((cos . (exp_R . x)) ^2 ) by SIN_COS:70 ;
hence ((tan * exp_R ) `| Z) . x = (exp_R . x) / ((cos . (exp_R . x)) ^2 ) by A4, A5, FDIFF_1:def 8; :: thesis: verum
end;
hence ( tan * exp_R is_differentiable_on Z & ( for x being Real st x in Z holds
((tan * exp_R ) `| Z) . x = (exp_R . x) / ((cos . (exp_R . x)) ^2 ) ) ) by A1, A3, FDIFF_1:16; :: thesis: verum