let Z be open Subset of REAL ; ( Z c= dom ((#Z 2) * (cos / sin )) & ( for x being Real st x in Z holds
sin . x <> 0 ) implies ( (#Z 2) * (cos / sin ) is_differentiable_on Z & ( for x being Real st x in Z holds
(((#Z 2) * (cos / sin )) `| Z) . x = - ((2 * (cos . x)) / ((sin . x) #Z 3)) ) ) )
assume that
A1:
Z c= dom ((#Z 2) * (cos / sin ))
and
A2:
for x being Real st x in Z holds
sin . x <> 0
; ( (#Z 2) * (cos / sin ) is_differentiable_on Z & ( for x being Real st x in Z holds
(((#Z 2) * (cos / sin )) `| Z) . x = - ((2 * (cos . x)) / ((sin . x) #Z 3)) ) )
for y being set st y in Z holds
y in dom (cos / sin )
by A1, FUNCT_1:21;
then A3:
Z c= dom (cos / sin )
by TARSKI:def 3;
A4:
for x being Real st x in Z holds
(#Z 2) * (cos / sin ) is_differentiable_in x
then A5:
(#Z 2) * (cos / sin ) is_differentiable_on Z
by A1, FDIFF_1:16;
for x being Real st x in Z holds
(((#Z 2) * (cos / sin )) `| Z) . x = - ((2 * (cos . x)) / ((sin . x) #Z 3))
proof
let x be
Real;
( x in Z implies (((#Z 2) * (cos / sin )) `| Z) . x = - ((2 * (cos . x)) / ((sin . x) #Z 3)) )
assume A6:
x in Z
;
(((#Z 2) * (cos / sin )) `| Z) . x = - ((2 * (cos . x)) / ((sin . x) #Z 3))
then A7:
(cos / sin ) . x =
(cos . x) * ((sin . x) " )
by A3, RFUNCT_1:def 4
.=
(cos . x) * (1 / (sin . x))
by XCMPLX_1:217
.=
(cos . x) / (sin . x)
by XCMPLX_1:100
;
A8:
sin . x <> 0
by A2, A6;
then A9:
cos / sin is_differentiable_in x
by Th47;
(((#Z 2) * (cos / sin )) `| Z) . x =
diff ((#Z 2) * (cos / sin )),
x
by A5, A6, FDIFF_1:def 8
.=
(2 * (((cos / sin ) . x) #Z (2 - 1))) * (diff (cos / sin ),x)
by A9, TAYLOR_1:3
.=
(2 * (((cos / sin ) . x) #Z (2 - 1))) * (- (1 / ((sin . x) ^2 )))
by A8, Th47
.=
- ((2 * (((cos / sin ) . x) #Z (2 - 1))) * (1 / ((sin . x) ^2 )))
.=
- ((2 * (((cos / sin ) . x) #Z 1)) / ((sin . x) ^2 ))
by XCMPLX_1:100
.=
- ((2 * ((cos . x) / (sin . x))) / ((sin . x) ^2 ))
by A7, PREPOWER:45
.=
- (((2 * (cos . x)) / (sin . x)) / ((sin . x) ^2 ))
by XCMPLX_1:75
.=
- ((2 * (cos . x)) / ((sin . x) * ((sin . x) ^2 )))
by XCMPLX_1:79
.=
- ((2 * (cos . x)) / ((sin . x) * ((sin . x) #Z 2)))
by Th1
.=
- ((2 * (cos . x)) / (((sin . x) #Z 1) * ((sin . x) #Z 2)))
by PREPOWER:45
.=
- ((2 * (cos . x)) / ((sin . x) #Z (1 + 2)))
by A2, A6, PREPOWER:54
.=
- ((2 * (cos . x)) / ((sin . x) #Z 3))
;
hence
(((#Z 2) * (cos / sin )) `| Z) . x = - ((2 * (cos . x)) / ((sin . x) #Z 3))
;
verum
end;
hence
( (#Z 2) * (cos / sin ) is_differentiable_on Z & ( for x being Real st x in Z holds
(((#Z 2) * (cos / sin )) `| Z) . x = - ((2 * (cos . x)) / ((sin . x) #Z 3)) ) )
by A1, A4, FDIFF_1:16; verum