let Z be open Subset of REAL ; for f1 being PartFunc of REAL ,REAL st Z c= dom (f1 + (2 (#) sin )) & ( for x being Real st x in Z holds
f1 . x = 1 ) holds
( f1 + (2 (#) sin ) is_differentiable_on Z & ( for x being Real st x in Z holds
((f1 + (2 (#) sin )) `| Z) . x = 2 * (cos . x) ) )
let f1 be PartFunc of REAL ,REAL ; ( Z c= dom (f1 + (2 (#) sin )) & ( for x being Real st x in Z holds
f1 . x = 1 ) implies ( f1 + (2 (#) sin ) is_differentiable_on Z & ( for x being Real st x in Z holds
((f1 + (2 (#) sin )) `| Z) . x = 2 * (cos . x) ) ) )
assume that
A1:
Z c= dom (f1 + (2 (#) sin ))
and
A2:
for x being Real st x in Z holds
f1 . x = 1
; ( f1 + (2 (#) sin ) is_differentiable_on Z & ( for x being Real st x in Z holds
((f1 + (2 (#) sin )) `| Z) . x = 2 * (cos . x) ) )
A3:
Z c= (dom f1) /\ (dom (2 (#) sin ))
by A1, VALUED_1:def 1;
then A4:
Z c= dom f1
by XBOOLE_1:18;
A5:
sin is_differentiable_on Z
by FDIFF_1:34, SIN_COS:73;
A6:
for x being Real st x in Z holds
f1 . x = (0 * x) + 1
by A2;
then A7:
f1 is_differentiable_on Z
by A4, FDIFF_1:31;
Z c= dom (2 (#) sin )
by A3, XBOOLE_1:18;
then A8:
2 (#) sin is_differentiable_on Z
by A5, FDIFF_1:28;
for x being Real st x in Z holds
((f1 + (2 (#) sin )) `| Z) . x = 2 * (cos . x)
proof
let x be
Real;
( x in Z implies ((f1 + (2 (#) sin )) `| Z) . x = 2 * (cos . x) )
A9:
sin is_differentiable_in x
by SIN_COS:69;
assume A10:
x in Z
;
((f1 + (2 (#) sin )) `| Z) . x = 2 * (cos . x)
then ((f1 + (2 (#) sin )) `| Z) . x =
(diff f1,x) + (diff (2 (#) sin ),x)
by A1, A7, A8, FDIFF_1:26
.=
((f1 `| Z) . x) + (diff (2 (#) sin ),x)
by A7, A10, FDIFF_1:def 8
.=
((f1 `| Z) . x) + (2 * (diff sin ,x))
by A9, FDIFF_1:23
.=
0 + (2 * (diff sin ,x))
by A4, A6, A10, FDIFF_1:31
.=
2
* (cos . x)
by SIN_COS:69
;
hence
((f1 + (2 (#) sin )) `| Z) . x = 2
* (cos . x)
;
verum
end;
hence
( f1 + (2 (#) sin ) is_differentiable_on Z & ( for x being Real st x in Z holds
((f1 + (2 (#) sin )) `| Z) . x = 2 * (cos . x) ) )
by A1, A7, A8, FDIFF_1:26; verum