let Z be open Subset of REAL ; ( Z c= dom (sin * arctan ) & Z c= ].(- 1),1.[ implies ( sin * arctan is_differentiable_on Z & ( for x being Real st x in Z holds
((sin * arctan ) `| Z) . x = (cos . (arctan . x)) / (1 + (x ^2 )) ) ) )
assume that
A1:
Z c= dom (sin * arctan )
and
A2:
Z c= ].(- 1),1.[
; ( sin * arctan is_differentiable_on Z & ( for x being Real st x in Z holds
((sin * arctan ) `| Z) . x = (cos . (arctan . x)) / (1 + (x ^2 )) ) )
A3:
for x being Real st x in Z holds
sin * arctan is_differentiable_in x
then A6:
sin * arctan is_differentiable_on Z
by A1, FDIFF_1:16;
for x being Real st x in Z holds
((sin * arctan ) `| Z) . x = (cos . (arctan . x)) / (1 + (x ^2 ))
proof
let x be
Real;
( x in Z implies ((sin * arctan ) `| Z) . x = (cos . (arctan . x)) / (1 + (x ^2 )) )
assume A7:
x in Z
;
((sin * arctan ) `| Z) . x = (cos . (arctan . x)) / (1 + (x ^2 ))
A8:
arctan is_differentiable_on Z
by A2, SIN_COS9:81;
then A9:
arctan is_differentiable_in x
by A7, FDIFF_1:16;
A10:
sin is_differentiable_in arctan . x
by SIN_COS:69;
((sin * arctan ) `| Z) . x =
diff (sin * arctan ),
x
by A6, A7, FDIFF_1:def 8
.=
(diff sin ,(arctan . x)) * (diff arctan ,x)
by A9, A10, FDIFF_2:13
.=
(cos . (arctan . x)) * (diff arctan ,x)
by SIN_COS:69
.=
(cos . (arctan . x)) * ((arctan `| Z) . x)
by A7, A8, FDIFF_1:def 8
.=
(cos . (arctan . x)) * (1 / (1 + (x ^2 )))
by A2, A7, SIN_COS9:81
.=
(cos . (arctan . x)) / (1 + (x ^2 ))
;
hence
((sin * arctan ) `| Z) . x = (cos . (arctan . x)) / (1 + (x ^2 ))
;
verum
end;
hence
( sin * arctan is_differentiable_on Z & ( for x being Real st x in Z holds
((sin * arctan ) `| Z) . x = (cos . (arctan . x)) / (1 + (x ^2 )) ) )
by A1, A3, FDIFF_1:16; verum