let R be RelStr ; for N being Subset of R
for x being Element of (R \~ ) st R is quasi_ordered & x in N & (the InternalRel of R -Seg x) /\ N c= Class (EqRel R),x holds
x is_minimal_wrt N,the InternalRel of (R \~ )
let N be Subset of R; for x being Element of (R \~ ) st R is quasi_ordered & x in N & (the InternalRel of R -Seg x) /\ N c= Class (EqRel R),x holds
x is_minimal_wrt N,the InternalRel of (R \~ )
let x be Element of (R \~ ); ( R is quasi_ordered & x in N & (the InternalRel of R -Seg x) /\ N c= Class (EqRel R),x implies x is_minimal_wrt N,the InternalRel of (R \~ ) )
assume that
A1:
R is quasi_ordered
and
A2:
x in N
and
A3:
(the InternalRel of R -Seg x) /\ N c= Class (EqRel R),x
; x is_minimal_wrt N,the InternalRel of (R \~ )
set IR = the InternalRel of R;
set IR9 = the InternalRel of (R \~ );
now assume
ex
y being
set st
(
y in N &
y <> x &
[y,x] in the
InternalRel of
(R \~ ) )
;
contradictionthen consider y being
set such that A4:
y in N
and A5:
y <> x
and A6:
[y,x] in the
InternalRel of
(R \~ )
;
A7:
not
[y,x] in the
InternalRel of
R ~
by A6, XBOOLE_0:def 5;
y in the
InternalRel of
R -Seg x
by A5, A6, WELLORD1:def 1;
then
y in (the InternalRel of R -Seg x) /\ N
by A4, XBOOLE_0:def 4;
then
[y,x] in EqRel R
by A3, EQREL_1:27;
then
[y,x] in the
InternalRel of
R /\ (the InternalRel of R ~ )
by A1, Def4;
hence
contradiction
by A7, XBOOLE_0:def 4;
verum end;
hence
x is_minimal_wrt N,the InternalRel of (R \~ )
by A2, WAYBEL_4:def 26; verum