let X be OrtAfPl; ex a, b, c being Element of X st
( LIN a,b,c & a <> b & b <> c & c <> a )
consider a, p being Element of X such that
A1:
a <> p
by ANALMETR:51;
consider b being Element of X such that
A2:
a,p _|_ p,b
and
A3:
p <> b
by ANALMETR:51;
reconsider a9 = a, b9 = b, p9 = p as Element of (Af X) by ANALMETR:47;
consider c being Element of X such that
A4:
p,c _|_ a,b
and
A5:
LIN a,b,c
by ANALMETR:91;
take
a
; ex b, c being Element of X st
( LIN a,b,c & a <> b & b <> c & c <> a )
take
b
; ex c being Element of X st
( LIN a,b,c & a <> b & b <> c & c <> a )
take
c
; ( LIN a,b,c & a <> b & b <> c & c <> a )
thus
LIN a,b,c
by A5; ( a <> b & b <> c & c <> a )
thus
a <> b
( b <> c & c <> a )
thus
b <> c
c <> aproof
assume
not
b <> c
;
contradiction
then
a,
p // a,
b
by A2, A3, A4, ANALMETR:85;
then
LIN a,
p,
b
by ANALMETR:def 11;
then
LIN a9,
p9,
b9
by ANALMETR:55;
then
LIN p9,
a9,
b9
by AFF_1:15;
then
LIN p,
a,
b
by ANALMETR:55;
then
p,
a // p,
b
by ANALMETR:def 11;
then
a,
p _|_ p,
a
by A2, A3, ANALMETR:84;
then
a,
p _|_ a,
p
by ANALMETR:83;
hence
contradiction
by A1, ANALMETR:51;
verum
end;
assume
not c <> a
; contradiction
then
a,p _|_ a,b
by A4, ANALMETR:83;
then
p,b // a,b
by A1, A2, ANALMETR:85;
then
b,p // b,a
by ANALMETR:81;
then
LIN b,p,a
by ANALMETR:def 11;
then
LIN b9,p9,a9
by ANALMETR:55;
then
LIN p9,a9,b9
by AFF_1:15;
then
LIN p,a,b
by ANALMETR:55;
then
p,a // p,b
by ANALMETR:def 11;
then
a,p _|_ p,a
by A2, A3, ANALMETR:84;
then
a,p _|_ a,p
by ANALMETR:83;
hence
contradiction
by A1, ANALMETR:51; verum