now let y be
set ;
( ( y in [.(- 1),1.] implies ex x being set st
( x in dom cos & y = cos . x ) ) & ( ex x being set st
( x in dom cos & y = cos . x ) implies y in [.(- 1),1.] ) )thus
(
y in [.(- 1),1.] implies ex
x being
set st
(
x in dom cos &
y = cos . x ) )
( ex x being set st
( x in dom cos & y = cos . x ) implies y in [.(- 1),1.] )proof
assume A1:
y in [.(- 1),1.]
;
ex x being set st
( x in dom cos & y = cos . x )
then reconsider y1 =
y as
Real ;
(
cos | [.0 ,PI .] is
continuous &
y1 in [.(cos . 0 ),(cos . PI ).] \/ [.(cos . PI ),(cos . 0 ).] )
by A1, SIN_COS:33, SIN_COS:81, XBOOLE_0:def 3;
then consider x being
Real such that
x in [.0 ,PI .]
and A2:
y1 = cos . x
by FCONT_2:16, SIN_COS:27;
take
x
;
( x in dom cos & y = cos . x )
thus
(
x in dom cos &
y = cos . x )
by A2, SIN_COS:27;
verum
end; thus
( ex
x being
set st
(
x in dom cos &
y = cos . x ) implies
y in [.(- 1),1.] )
by Th45, SIN_COS:27;
verum end;
hence
rng cos = [.(- 1),1.]
by FUNCT_1:def 5; verum