let K, M, N be Cardinal; exp (K *` M),N = (exp K,N) *` (exp M,N)
( card (K *` M) = K *` M & card N = card N )
;
hence exp (K *` M),N =
card (Funcs N,[:K,M:])
by FUNCT_5:68
.=
card [:(Funcs N,K),(Funcs N,M):]
by FUNCT_5:71
.=
(exp K,N) *` (exp M,N)
by Th14
;
verum