let i, j, m, n be Element of NAT ; ( i = min i,j,m,n implies ( i <= j & i <= m & i <= n ) )
A1:
min m,n <= n
by XXREAL_0:17;
assume
i = min i,j,m,n
; ( i <= j & i <= m & i <= n )
then A2:
( i <= min i,j & i <= min m,n )
by XXREAL_0:17;
( min i,j <= j & min m,n <= m )
by XXREAL_0:17;
hence
( i <= j & i <= m & i <= n )
by A2, A1, XXREAL_0:2; verum