let i, j, m, n be Element of NAT ; for X being BCI-algebra of i,j,m,n
for k being Element of NAT holds X is BCI-algebra of i,j + k,m + k,n
let X be BCI-algebra of i,j,m,n; for k being Element of NAT holds X is BCI-algebra of i,j + k,m + k,n
let k be Element of NAT ; X is BCI-algebra of i,j + k,m + k,n
for x, y being Element of X holds Polynom i,(j + k),x,y = Polynom (m + k),n,y,x
proof
let x,
y be
Element of
X;
Polynom i,(j + k),x,y = Polynom (m + k),n,y,x
A1:
(Polynom m,n,y,x),
(y \ x) to_power k =
((y,(y \ x) to_power (m + 1)),(y \ x) to_power k),
(x \ y) to_power n
by BCIALG_2:11
.=
(y,(y \ x) to_power ((m + 1) + k)),
(x \ y) to_power n
by BCIALG_2:10
.=
Polynom (m + k),
n,
y,
x
;
(Polynom i,j,x,y),
(y \ x) to_power k = Polynom i,
(j + k),
x,
y
by BCIALG_2:10;
hence
Polynom i,
(j + k),
x,
y = Polynom (m + k),
n,
y,
x
by A1, Def3;
verum
end;
hence
X is BCI-algebra of i,j + k,m + k,n
by Def3; verum