let i, j, m, n be Element of NAT ; for X being BCI-algebra of i,j,m,n
for k being Element of NAT holds X is BCI-algebra of i + k,j,m,n + k
let X be BCI-algebra of i,j,m,n; for k being Element of NAT holds X is BCI-algebra of i + k,j,m,n + k
let k be Element of NAT ; X is BCI-algebra of i + k,j,m,n + k
for x, y being Element of X holds Polynom (i + k),j,x,y = Polynom m,(n + k),y,x
proof
let x,
y be
Element of
X;
Polynom (i + k),j,x,y = Polynom m,(n + k),y,x
A1:
(Polynom m,n,y,x),
(x \ y) to_power k = Polynom m,
(n + k),
y,
x
by BCIALG_2:10;
(Polynom i,j,x,y),
(x \ y) to_power k =
((x,(x \ y) to_power (i + 1)),(x \ y) to_power k),
(y \ x) to_power j
by BCIALG_2:11
.=
(x,(x \ y) to_power ((i + 1) + k)),
(y \ x) to_power j
by BCIALG_2:10
.=
Polynom (i + k),
j,
x,
y
;
hence
Polynom (i + k),
j,
x,
y = Polynom m,
(n + k),
y,
x
by A1, Def3;
verum
end;
hence
X is BCI-algebra of i + k,j,m,n + k
by Def3; verum