let AP be AffinPlane; ( AP is Pappian iff AP is satisfying_PAP_1 )
A1:
now assume A2:
AP is
satisfying_PAP_1
;
AP is Pappian thus
AP is
Pappian
verumproof
let M be
Subset of
AP;
AFF_2:def 2 for N being Subset of AP
for o, a, b, c, a9, b9, c9 being Element of AP st M is being_line & N is being_line & M <> N & o in M & o in N & o <> a & o <> a9 & o <> b & o <> b9 & o <> c & o <> c9 & a in M & b in M & c in M & a9 in N & b9 in N & c9 in N & a,b9 // b,a9 & b,c9 // c,b9 holds
a,c9 // c,a9let N be
Subset of
AP;
for o, a, b, c, a9, b9, c9 being Element of AP st M is being_line & N is being_line & M <> N & o in M & o in N & o <> a & o <> a9 & o <> b & o <> b9 & o <> c & o <> c9 & a in M & b in M & c in M & a9 in N & b9 in N & c9 in N & a,b9 // b,a9 & b,c9 // c,b9 holds
a,c9 // c,a9let o,
a,
b,
c,
a9,
b9,
c9 be
Element of
AP;
( M is being_line & N is being_line & M <> N & o in M & o in N & o <> a & o <> a9 & o <> b & o <> b9 & o <> c & o <> c9 & a in M & b in M & c in M & a9 in N & b9 in N & c9 in N & a,b9 // b,a9 & b,c9 // c,b9 implies a,c9 // c,a9 )
assume that A3:
M is
being_line
and A4:
N is
being_line
and A5:
(
M <> N &
o in M &
o in N )
and A6:
o <> a
and A7:
o <> a9
and A8:
o <> b
and A9:
o <> b9
and A10:
(
o <> c &
o <> c9 )
and A11:
a in M
and A12:
b in M
and A13:
c in M
and A14:
a9 in N
and A15:
b9 in N
and A16:
c9 in N
and A17:
a,
b9 // b,
a9
and A18:
b,
c9 // c,
b9
;
a,c9 // c,a9
set A =
Line a,
c9;
set P =
Line b,
a9;
A19:
b <> a9
by A3, A4, A5, A7, A12, A14, AFF_1:30;
then A20:
b in Line b,
a9
by AFF_1:38;
assume A21:
not
a,
c9 // c,
a9
;
contradiction
then A22:
a <> c9
by AFF_1:12;
then A23:
(
a in Line a,
c9 &
c9 in Line a,
c9 )
by AFF_1:38;
A24:
a9 in Line b,
a9
by A19, AFF_1:38;
Line a,
c9 is
being_line
by A22, AFF_1:38;
then consider K being
Subset of
AP such that A25:
c in K
and A26:
Line a,
c9 // K
by AFF_1:63;
A27:
b <> c
proof
assume A28:
b = c
;
contradiction
then
LIN b,
c9,
b9
by A18, AFF_1:def 1;
then
LIN b9,
c9,
b
by AFF_1:15;
then
(
b9 = c9 or
b in N )
by A4, A15, A16, AFF_1:39;
hence
contradiction
by A3, A4, A5, A8, A12, A17, A21, A28, AFF_1:30;
verum
end;
A29:
b9 <> c9
proof
assume
b9 = c9
;
contradiction
then
b9,
b // b9,
c
by A18, AFF_1:13;
then
LIN b9,
b,
c
by AFF_1:def 1;
then
LIN b,
c,
b9
by AFF_1:15;
then
b9 in M
by A3, A12, A13, A27, AFF_1:39;
hence
contradiction
by A3, A4, A5, A9, A15, AFF_1:30;
verum
end;
A30:
not
Line b,
a9 // K
proof
assume
Line b,
a9 // K
;
contradiction
then
Line b,
a9 // Line a,
c9
by A26, AFF_1:58;
then
b,
a9 // a,
c9
by A23, A20, A24, AFF_1:53;
then
a,
b9 // a,
c9
by A17, A19, AFF_1:14;
then
LIN a,
b9,
c9
by AFF_1:def 1;
then
LIN b9,
c9,
a
by AFF_1:15;
then
a in N
by A4, A15, A16, A29, AFF_1:39;
hence
contradiction
by A3, A4, A5, A6, A11, AFF_1:30;
verum
end;
A31:
Line b,
a9 is
being_line
by A19, AFF_1:38;
K is
being_line
by A26, AFF_1:50;
then consider x being
Element of
AP such that A32:
x in Line b,
a9
and A33:
x in K
by A31, A30, AFF_1:72;
A34:
a,
c9 // c,
x
by A23, A25, A26, A33, AFF_1:53;
LIN b,
x,
a9
by A31, A20, A24, A32, AFF_1:33;
then
b,
x // b,
a9
by AFF_1:def 1;
then
a,
b9 // b,
x
by A17, A19, AFF_1:14;
then
x in N
by A2, A3, A4, A5, A6, A8, A9, A10, A11, A12, A13, A15, A16, A18, A27, A34, Def3;
then
N = Line b,
a9
by A4, A14, A21, A31, A24, A32, A34, AFF_1:30;
hence
contradiction
by A3, A4, A5, A8, A12, A20, AFF_1:30;
verum
end; end;
now assume A35:
AP is
Pappian
;
AP is satisfying_PAP_1 thus
AP is
satisfying_PAP_1
verumproof
let M be
Subset of
AP;
AFF_2:def 3 for N being Subset of AP
for o, a, b, c, a9, b9, c9 being Element of AP st M is being_line & N is being_line & M <> N & o in M & o in N & o <> a & o <> a9 & o <> b & o <> b9 & o <> c & o <> c9 & a in M & b in M & c in M & b9 in N & c9 in N & a,b9 // b,a9 & b,c9 // c,b9 & a,c9 // c,a9 & b <> c holds
a9 in Nlet N be
Subset of
AP;
for o, a, b, c, a9, b9, c9 being Element of AP st M is being_line & N is being_line & M <> N & o in M & o in N & o <> a & o <> a9 & o <> b & o <> b9 & o <> c & o <> c9 & a in M & b in M & c in M & b9 in N & c9 in N & a,b9 // b,a9 & b,c9 // c,b9 & a,c9 // c,a9 & b <> c holds
a9 in Nlet o,
a,
b,
c,
a9,
b9,
c9 be
Element of
AP;
( M is being_line & N is being_line & M <> N & o in M & o in N & o <> a & o <> a9 & o <> b & o <> b9 & o <> c & o <> c9 & a in M & b in M & c in M & b9 in N & c9 in N & a,b9 // b,a9 & b,c9 // c,b9 & a,c9 // c,a9 & b <> c implies a9 in N )
assume that A36:
M is
being_line
and A37:
N is
being_line
and A38:
M <> N
and A39:
o in M
and A40:
o in N
and A41:
o <> a
and
o <> a9
and A42:
o <> b
and A43:
o <> b9
and A44:
o <> c
and A45:
o <> c9
and A46:
a in M
and A47:
b in M
and A48:
c in M
and A49:
b9 in N
and A50:
c9 in N
and A51:
a,
b9 // b,
a9
and A52:
b,
c9 // c,
b9
and A53:
a,
c9 // c,
a9
and A54:
b <> c
;
a9 in N
A55:
a <> c9
by A36, A37, A38, A39, A40, A41, A46, A50, AFF_1:30;
A56:
b <> a9
proof
assume
b = a9
;
contradiction
then
c,
b // a,
c9
by A53, AFF_1:13;
then
c9 in M
by A36, A46, A47, A48, A54, AFF_1:62;
hence
contradiction
by A36, A37, A38, A39, A40, A45, A50, AFF_1:30;
verum
end;
not
b,
a9 // N
proof
assume A57:
b,
a9 // N
;
contradiction
b,
a9 // a,
b9
by A51, AFF_1:13;
then
a,
b9 // N
by A56, A57, AFF_1:46;
then
b9,
a // N
by AFF_1:48;
then
a in N
by A37, A49, AFF_1:37;
hence
contradiction
by A36, A37, A38, A39, A40, A41, A46, AFF_1:30;
verum
end;
then consider x being
Element of
AP such that A58:
x in N
and A59:
LIN b,
a9,
x
by A37, AFF_1:73;
A60:
b,
a9 // b,
x
by A59, AFF_1:def 1;
A61:
o <> x
proof
assume
o = x
;
contradiction
then
b,
o // a,
b9
by A51, A56, A60, AFF_1:14;
then
b9 in M
by A36, A39, A42, A46, A47, AFF_1:62;
hence
contradiction
by A36, A37, A38, A39, A40, A43, A49, AFF_1:30;
verum
end;
a,
b9 // b,
x
by A51, A56, A60, AFF_1:14;
then
a,
c9 // c,
x
by A35, A36, A37, A38, A39, A40, A41, A42, A43, A44, A45, A46, A47, A48, A49, A50, A52, A58, A61, Def2;
then
c,
a9 // c,
x
by A53, A55, AFF_1:14;
then
LIN c,
a9,
x
by AFF_1:def 1;
then A62:
LIN a9,
x,
c
by AFF_1:15;
A63:
LIN a9,
x,
x
by AFF_1:16;
assume A64:
not
a9 in N
;
contradiction
LIN a9,
x,
b
by A59, AFF_1:15;
then
x in M
by A36, A47, A48, A54, A64, A58, A62, A63, AFF_1:17, AFF_1:39;
hence
contradiction
by A36, A37, A38, A39, A40, A58, A61, AFF_1:30;
verum
end; end;
hence
( AP is Pappian iff AP is satisfying_PAP_1 )
by A1; verum