let t be finite DecoratedTree; for p being Node of t
for q being Node of (t | p) holds succ t,(p ^ q) = succ (t | p),q
let p be Node of t; for q being Node of (t | p) holds succ t,(p ^ q) = succ (t | p),q
let q be Node of (t | p); succ t,(p ^ q) = succ (t | p),q
A1:
dom (t | p) = (dom t) | p
by TREES_2:def 11;
then reconsider pq = p ^ q as Element of dom t by TREES_1:def 9;
reconsider q = q as Element of dom (t | p) ;
dom t = (dom t) with-replacement p,((dom t) | p)
by TREES_2:8;
then
succ pq, succ q are_equipotent
by A1, TREES_2:39;
then A2:
card (succ q) = card (succ pq)
by CARD_1:21;
A3:
ex r being Element of dom (t | p) st
( r = q & succ (t | p),q = (t | p) * (r succ ) )
by Def6;
rng (q succ ) c= dom (t | p)
;
then A4:
dom (succ (t | p),q) = dom (q succ )
by A3, RELAT_1:46;
A5:
ex q being Element of dom t st
( q = pq & succ t,pq = t * (q succ ) )
by Def6;
rng (pq succ ) c= dom t
;
then A6:
dom (succ t,pq) = dom (pq succ )
by A5, RELAT_1:46;
A7:
len (q succ ) = card (succ q)
by Def5;
A8:
len (pq succ ) = card (succ pq)
by Def5;
then A9:
dom (pq succ ) = dom (q succ )
by A7, A2, FINSEQ_3:31;
now let i be
Nat;
( i in dom (q succ ) implies (succ t,pq) . i = (succ (t | p),q) . i )assume A10:
i in dom (q succ )
;
(succ t,pq) . i = (succ (t | p),q) . ithen consider k being
Element of
NAT such that A11:
i = k + 1
and A12:
k < len (q succ )
by Lm1;
A13:
q ^ <*k*> in succ q
by A7, A12, Th7;
thus (succ t,pq) . i =
t . ((pq succ ) . i)
by A5, A9, A6, A10, FUNCT_1:22
.=
t . (pq ^ <*k*>)
by A8, A7, A2, A11, A12, Def5
.=
t . (p ^ (q ^ <*k*>))
by FINSEQ_1:45
.=
(t | p) . (q ^ <*k*>)
by A1, A13, TREES_2:def 11
.=
(t | p) . ((q succ ) . i)
by A11, A12, Def5
.=
(succ (t | p),q) . i
by A3, A4, A10, FUNCT_1:22
;
verum end;
hence
succ t,(p ^ q) = succ (t | p),q
by A9, A6, A4, FINSEQ_1:17; verum