defpred S1[ real number , set ] means $2 = |[(cos (((2 * PI ) * r) * $1)),(sin (((2 * PI ) * r) * $1))]|;
A1:
for x being Element of I[01] ex y being Element of the carrier of (Tunit_circle 2) st S1[x,y]
proof
let x be
Element of
I[01] ;
ex y being Element of the carrier of (Tunit_circle 2) st S1[x,y]
set y =
|[(cos (((2 * PI ) * r) * x)),(sin (((2 * PI ) * r) * x))]|;
|.(|[(cos (((2 * PI ) * r) * x)),(sin (((2 * PI ) * r) * x))]| - |[0 ,0 ]|).| =
|.|[(cos (((2 * PI ) * r) * x)),(sin (((2 * PI ) * r) * x))]|.|
by EUCLID:58, RLVECT_1:26
.=
sqrt (((|[(cos (((2 * PI ) * r) * x)),(sin (((2 * PI ) * r) * x))]| `1 ) ^2 ) + ((|[(cos (((2 * PI ) * r) * x)),(sin (((2 * PI ) * r) * x))]| `2 ) ^2 ))
by JGRAPH_1:47
.=
sqrt (((cos (((2 * PI ) * r) * x)) ^2 ) + ((|[(cos (((2 * PI ) * r) * x)),(sin (((2 * PI ) * r) * x))]| `2 ) ^2 ))
by EUCLID:56
.=
sqrt (((cos (((2 * PI ) * r) * x)) ^2 ) + ((sin (((2 * PI ) * r) * x)) ^2 ))
by EUCLID:56
.=
1
by SIN_COS:32, SQUARE_1:83
;
then reconsider y =
|[(cos (((2 * PI ) * r) * x)),(sin (((2 * PI ) * r) * x))]| as
Element of the
carrier of
(Tunit_circle 2) by Lm11, TOPREAL9:9;
take
y
;
S1[x,y]
thus
S1[
x,
y]
;
verum
end;
ex f being Function of the carrier of I[01] ,the carrier of (Tunit_circle 2) st
for x being Element of I[01] holds S1[x,f . x]
from FUNCT_2:sch 3(A1);
hence
ex b1 being Function of I[01] ,(Tunit_circle 2) st
for x being Point of I[01] holds b1 . x = |[(cos (((2 * PI ) * r) * x)),(sin (((2 * PI ) * r) * x))]|
; verum