let N be non empty MetrStruct ; for C being Subset of N holds
( ( C <> {} & C is bounded implies ex r being Real ex w being Element of N st
( 0 < r & w in C & ( for z being Point of N st z in C holds
dist w,z <= r ) ) ) & ( N is symmetric & N is triangle & ex r being Real ex w being Element of N st
( 0 < r & ( for z being Point of N st z in C holds
dist w,z <= r ) ) implies C is bounded ) )
let C be Subset of N; ( ( C <> {} & C is bounded implies ex r being Real ex w being Element of N st
( 0 < r & w in C & ( for z being Point of N st z in C holds
dist w,z <= r ) ) ) & ( N is symmetric & N is triangle & ex r being Real ex w being Element of N st
( 0 < r & ( for z being Point of N st z in C holds
dist w,z <= r ) ) implies C is bounded ) )
thus
( C <> {} & C is bounded implies ex r being Real ex w being Element of N st
( 0 < r & w in C & ( for z being Point of N st z in C holds
dist w,z <= r ) ) )
( N is symmetric & N is triangle & ex r being Real ex w being Element of N st
( 0 < r & ( for z being Point of N st z in C holds
dist w,z <= r ) ) implies C is bounded )proof
consider w being
Element of
C;
assume A1:
C <> {}
;
( not C is bounded or ex r being Real ex w being Element of N st
( 0 < r & w in C & ( for z being Point of N st z in C holds
dist w,z <= r ) ) )
then reconsider w =
w as
Point of
N by TARSKI:def 3;
assume
C is
bounded
;
ex r being Real ex w being Element of N st
( 0 < r & w in C & ( for z being Point of N st z in C holds
dist w,z <= r ) )
then consider r being
Real such that A2:
0 < r
and A3:
for
x,
y being
Point of
N st
x in C &
y in C holds
dist x,
y <= r
by Def9;
take
r
;
ex w being Element of N st
( 0 < r & w in C & ( for z being Point of N st z in C holds
dist w,z <= r ) )
take
w
;
( 0 < r & w in C & ( for z being Point of N st z in C holds
dist w,z <= r ) )
thus
0 < r
by A2;
( w in C & ( for z being Point of N st z in C holds
dist w,z <= r ) )
thus
w in C
by A1;
for z being Point of N st z in C holds
dist w,z <= r
let z be
Point of
N;
( z in C implies dist w,z <= r )
assume
z in C
;
dist w,z <= r
hence
dist w,
z <= r
by A3;
verum
end;
assume A4:
N is symmetric
; ( not N is triangle or for r being Real
for w being Element of N holds
( not 0 < r or ex z being Point of N st
( z in C & not dist w,z <= r ) ) or C is bounded )
assume A5:
N is triangle
; ( for r being Real
for w being Element of N holds
( not 0 < r or ex z being Point of N st
( z in C & not dist w,z <= r ) ) or C is bounded )
given r being Real, w being Element of N such that A6:
0 < r
and
A7:
for z being Point of N st z in C holds
dist w,z <= r
; C is bounded
set s = r + r;
ex s being Real st
( 0 < s & ( for x, y being Point of N st x in C & y in C holds
dist x,y <= s ) )
proof
take
r + r
;
( 0 < r + r & ( for x, y being Point of N st x in C & y in C holds
dist x,y <= r + r ) )
thus
0 < r + r
by A6;
for x, y being Point of N st x in C & y in C holds
dist x,y <= r + r
let x,
y be
Point of
N;
( x in C & y in C implies dist x,y <= r + r )
assume that A8:
x in C
and A9:
y in C
;
dist x,y <= r + r
dist w,
x <= r
by A7, A8;
then A10:
dist x,
w <= r
by A4, METRIC_1:3;
dist w,
y <= r
by A7, A9;
then A11:
(dist x,w) + (dist w,y) <= r + r
by A10, XREAL_1:9;
dist x,
y <= (dist x,w) + (dist w,y)
by A5, METRIC_1:4;
hence
dist x,
y <= r + r
by A11, XXREAL_0:2;
verum
end;
hence
C is bounded
by Def9; verum