reconsider fZ = f | Z as Element of PFuncs REAL ,REAL by PARTFUN1:119;
defpred S1[ set , set , set ] means ex h being PartFunc of REAL ,REAL st
( $2 = h & $3 = h `| Z );
A1:
for n being Element of NAT
for x being Element of PFuncs REAL ,REAL ex y being Element of PFuncs REAL ,REAL st S1[n,x,y]
proof
let n be
Element of
NAT ;
for x being Element of PFuncs REAL ,REAL ex y being Element of PFuncs REAL ,REAL st S1[n,x,y]let x be
Element of
PFuncs REAL ,
REAL ;
ex y being Element of PFuncs REAL ,REAL st S1[n,x,y]
reconsider x9 =
x as
PartFunc of
REAL ,
REAL by PARTFUN1:120;
reconsider y =
x9 `| Z as
Element of
PFuncs REAL ,
REAL by PARTFUN1:119;
ex
h being
PartFunc of
REAL ,
REAL st
(
x = h &
y = h `| Z )
;
hence
ex
y being
Element of
PFuncs REAL ,
REAL st
S1[
n,
x,
y]
;
verum
end;
consider g being Function of NAT ,(PFuncs REAL ,REAL ) such that
A2:
( g . 0 = fZ & ( for n being Element of NAT holds S1[n,g . n,g . (n + 1)] ) )
from RECDEF_1:sch 2(A1);
defpred S2[ Element of NAT ] means g . $1 is PartFunc of REAL ,REAL ;
reconsider g = g as Functional_Sequence of REAL ,REAL ;
take
g
; ( g . 0 = f | Z & ( for i being natural number holds g . (i + 1) = (g . i) `| Z ) )
thus
g . 0 = f | Z
by A2; for i being natural number holds g . (i + 1) = (g . i) `| Z
let i be natural number ; g . (i + 1) = (g . i) `| Z
i is Element of NAT
by ORDINAL1:def 13;
then
S1[i,g . i,g . (i + 1)]
by A2;
hence
g . (i + 1) = (g . i) `| Z
; verum