set f = sin ^ ;
[.(- (PI / 2)),0 .[ /\ (sin " {0 }) = {}
proof
assume
[.(- (PI / 2)),0 .[ /\ (sin " {0 }) <> {}
;
contradiction
then consider rr being
set such that A1:
rr in [.(- (PI / 2)),0 .[ /\ (sin " {0 })
by XBOOLE_0:def 1;
A2:
rr in sin " {0 }
by A1, XBOOLE_0:def 4;
A3:
rr in [.(- (PI / 2)),0 .[
by A1, XBOOLE_0:def 4;
reconsider rr =
rr as
real number by A1;
rr < 0
by A3, Lm3, XXREAL_1:4;
then A4:
rr + (2 * PI ) < 0 + (2 * PI )
by XREAL_1:10;
- PI < rr
by A3, Lm3, XXREAL_1:4;
then
(- PI ) + (2 * PI ) < rr + (2 * PI )
by XREAL_1:10;
then
rr + (2 * PI ) in ].PI ,(2 * PI ).[
by A4;
then
sin . (rr + (2 * PI )) < 0
by COMPTRIG:25;
then A5:
sin . rr <> 0
by SIN_COS:83;
sin . rr in {0 }
by A2, FUNCT_1:def 13;
hence
contradiction
by A5, TARSKI:def 1;
verum
end;
then
( [.(- (PI / 2)),0 .[ \ (sin " {0 }) c= (dom sin ) \ (sin " {0 }) & [.(- (PI / 2)),0 .[ misses sin " {0 } )
by SIN_COS:27, XBOOLE_0:def 7, XBOOLE_1:33;
then
[.(- (PI / 2)),0 .[ c= (dom sin ) \ (sin " {0 })
by XBOOLE_1:83;
hence
[.(- (PI / 2)),0 .[ c= dom cosec
by RFUNCT_1:def 8; verum