let E be non empty finite set ; for A, B being Event of E st 0 < prob A & prob B < 1 & A misses B holds
prob A,(B ` ) = (prob A) / (1 - (prob B))
let A, B be Event of E; ( 0 < prob A & prob B < 1 & A misses B implies prob A,(B ` ) = (prob A) / (1 - (prob B)) )
assume that
A1:
0 < prob A
and
A2:
prob B < 1
and
A3:
A misses B
; prob A,(B ` ) = (prob A) / (1 - (prob B))
(prob B) - 1 < 1 - 1
by A2, XREAL_1:11;
then
0 < - (- (1 - (prob B)))
;
then A4:
0 < prob (B ` )
by Th48;
then
(prob A) * (prob (B ` ),A) = (prob (B ` )) * (prob A,(B ` ))
by A1, Th69;
then
(prob A) * 1 = (prob (B ` )) * (prob A,(B ` ))
by A1, A3, Th75;
then
(prob A) * ((prob (B ` )) " ) = (prob A,(B ` )) * ((prob (B ` )) * ((prob (B ` )) " ))
;
then A5:
(prob A) * ((prob (B ` )) " ) = (prob A,(B ` )) * 1
by A4, XCMPLX_0:def 7;
prob (B ` ) = 1 - (prob B)
by Th48;
hence
prob A,(B ` ) = (prob A) / (1 - (prob B))
by A5, XCMPLX_0:def 9; verum