let f be circular s.c.c. FinSequence of (TOP-REAL 2); ( len f > 4 implies (LSeg f,((len f) -' 1)) /\ (LSeg f,1) = {(f /. 1)} )
assume A1:
len f > 4
; (LSeg f,((len f) -' 1)) /\ (LSeg f,1) = {(f /. 1)}
then A2:
((len f) -' 1) + 1 = len f
by XREAL_1:237, XXREAL_0:2;
A3:
len f >= 1 + 1
by A1, XXREAL_0:2;
then A4:
1 <= (len f) -' 1
by NAT_D:55;
A5:
len f >= (1 + 1) + 1
by A1, XXREAL_0:2;
thus
(LSeg f,((len f) -' 1)) /\ (LSeg f,1) c= {(f /. 1)}
XBOOLE_0:def 10 {(f /. 1)} c= (LSeg f,((len f) -' 1)) /\ (LSeg f,1)proof
assume
not
(LSeg f,((len f) -' 1)) /\ (LSeg f,1) c= {(f /. 1)}
;
contradiction
then consider p being
Point of
(TOP-REAL 2) such that A6:
p in (LSeg f,((len f) -' 1)) /\ (LSeg f,1)
and A7:
not
p in {(f /. 1)}
by SUBSET_1:7;
A8:
p <> f /. 1
by A7, TARSKI:def 1;
A9:
(
LSeg f,
((len f) -' 1) = LSeg (f /. ((len f) -' 1)),
(f /. (len f)) &
LSeg f,1
= LSeg (f /. 1),
(f /. (1 + 1)) )
by A3, A2, A4, TOPREAL1:def 5;
A10:
f /. (len f) = f /. 1
by FINSEQ_6:def 1;
per cases
( f /. (1 + 1) in LSeg f,((len f) -' 1) or f /. ((len f) -' 1) in LSeg f,1 )
by A6, A9, A8, A10, JGRAPH_1:20;
suppose A11:
f /. (1 + 1) in LSeg f,
((len f) -' 1)
;
contradictionA12:
f /. (1 + 1) in LSeg f,
(1 + 1)
by A5, TOPREAL1:27;
3
+ 1
= 4
;
then
(1 + 1) + 1
< (len f) - 1
by A1, XREAL_1:22;
then A13:
(1 + 1) + 1
< (len f) -' 1
by A1, XREAL_1:235, XXREAL_0:2;
(len f) -' 1
< len f
by A4, NAT_D:51;
then
LSeg f,
(1 + 1) misses LSeg f,
((len f) -' 1)
by A13, GOBOARD5:def 4;
hence
contradiction
by A11, A12, XBOOLE_0:3;
verum end; suppose A14:
f /. ((len f) -' 1) in LSeg f,1
;
contradictionA15:
((len f) -' 2) + 1 =
(((len f) -' 1) -' 1) + 1
by NAT_D:45
.=
(len f) -' 1
by A3, NAT_D:55, XREAL_1:237
;
then A16:
((len f) -' 2) + 1
< len f
by A4, NAT_D:51;
2
+ 2
< len f
by A1;
then
1
+ 1
< (len f) - 2
by XREAL_1:22;
then
1
+ 1
< (len f) -' 2
by A1, XREAL_1:235, XXREAL_0:2;
then A17:
LSeg f,1
misses LSeg f,
((len f) -' 2)
by A16, GOBOARD5:def 4;
1
<= (len f) - 2
by A5, XREAL_1:21;
then
1
<= (len f) -' 2
by NAT_D:39;
then
f /. ((len f) -' 1) in LSeg f,
((len f) -' 2)
by A15, A16, TOPREAL1:27;
hence
contradiction
by A14, A17, XBOOLE_0:3;
verum end; end;
end;
let x be set ; TARSKI:def 3 ( not x in {(f /. 1)} or x in (LSeg f,((len f) -' 1)) /\ (LSeg f,1) )
assume
x in {(f /. 1)}
; x in (LSeg f,((len f) -' 1)) /\ (LSeg f,1)
then A18:
x = f /. 1
by TARSKI:def 1;
then
x = f /. (len f)
by FINSEQ_6:def 1;
then A19:
x in LSeg f,((len f) -' 1)
by A2, A4, TOPREAL1:27;
x in LSeg f,1
by A3, A18, TOPREAL1:27;
hence
x in (LSeg f,((len f) -' 1)) /\ (LSeg f,1)
by A19, XBOOLE_0:def 4; verum