let X be set ; for R being Relation holds R | X = R /\ [:X,(rng R):]
let R be Relation; R | X = R /\ [:X,(rng R):]
reconsider P = R /\ [:X,(rng R):] as Relation ;
for x, y being set holds
( [x,y] in R | X iff [x,y] in P )
proof
let x,
y be
set ;
( [x,y] in R | X iff [x,y] in P )
thus
(
[x,y] in R | X implies
[x,y] in P )
( [x,y] in P implies [x,y] in R | X )
assume A4:
[x,y] in P
;
[x,y] in R | X
then
[x,y] in [:X,(rng R):]
by XBOOLE_0:def 4;
then A5:
x in X
by ZFMISC_1:106;
[x,y] in R
by A4, XBOOLE_0:def 4;
hence
[x,y] in R | X
by A5, Def11;
verum
end;
hence
R | X = R /\ [:X,(rng R):]
by Def2; verum