let z, A, B, C, D, E be set ; ( z in [:A,B,C,D,E:] implies z = [(z `1_5 ),(z `2_5 ),(z `3_5 ),(z `4_5 ),(z `5_5 )] )
assume A1:
z in [:A,B,C,D,E:]
; z = [(z `1_5 ),(z `2_5 ),(z `3_5 ),(z `4_5 ),(z `5_5 )]
then A2:
( not C is empty & not D is empty )
by MCART_2:13;
A3:
not E is empty
by A1, MCART_2:13;
( not A is empty & not B is empty )
by A1, MCART_2:13;
then
ex a being Element of A ex b being Element of B ex c being Element of C ex d being Element of D ex e being Element of E st z = [a,b,c,d,e]
by A1, A2, A3, MCART_2:17;
hence
z = [(z `1_5 ),(z `2_5 ),(z `3_5 ),(z `4_5 ),(z `5_5 )]
by Th7; verum