let n, m be Nat; ( n <> 0 implies m = (((divSeq m,n) . 0 ) * n) + ((modSeq m,n) . 0 ) )
set fd = divSeq m,n;
set fm = modSeq m,n;
assume A1:
n <> 0
; m = (((divSeq m,n) . 0 ) * n) + ((modSeq m,n) . 0 )
( (divSeq m,n) . 0 = m div n & (modSeq m,n) . 0 = m mod n )
by Def2, Def3;
hence
m = (((divSeq m,n) . 0 ) * n) + ((modSeq m,n) . 0 )
by A1, NAT_D:2; verum