let n be Ordinal; for b1, b2 being bag of n holds
( not b1 < b2 iff b2 <=' b1 )
let b1, b2 be bag of n; ( not b1 < b2 iff b2 <=' b1 )
A1:
now assume A2:
not
b1 < b2
;
b2 <=' b1hence
b2 <=' b1
;
verum end;
now assume A3:
b2 <=' b1
;
not b1 < b2hence
not
b1 < b2
;
verum end;
hence
( not b1 < b2 iff b2 <=' b1 )
by A1; verum