let L be Field; for m being Element of NAT st m > 0 holds
for p, q being Polynomial of L holds (emb (2 * m),L) * ((1. L,(2 * m)) * (mConv (p *' q),(2 * m))) = (emb (2 * m),L) * (mConv (p *' q),(2 * m))
let m be Element of NAT ; ( m > 0 implies for p, q being Polynomial of L holds (emb (2 * m),L) * ((1. L,(2 * m)) * (mConv (p *' q),(2 * m))) = (emb (2 * m),L) * (mConv (p *' q),(2 * m)) )
assume A1:
m > 0
; for p, q being Polynomial of L holds (emb (2 * m),L) * ((1. L,(2 * m)) * (mConv (p *' q),(2 * m))) = (emb (2 * m),L) * (mConv (p *' q),(2 * m))
let p, q be Polynomial of L; (emb (2 * m),L) * ((1. L,(2 * m)) * (mConv (p *' q),(2 * m))) = (emb (2 * m),L) * (mConv (p *' q),(2 * m))
2 * m > 2 * 0
by A1, XREAL_1:70;
hence
(emb (2 * m),L) * ((1. L,(2 * m)) * (mConv (p *' q),(2 * m))) = (emb (2 * m),L) * (mConv (p *' q),(2 * m))
by Th35; verum