let X be non empty set ; for S being SigmaField of X
for M being sigma_Measure of S
for f being PartFunc of X,REAL
for A, B being Element of S st ex E being Element of S st
( E = dom f & f is_measurable_on E ) & f is nonnegative & A misses B holds
Integral M,(f | (A \/ B)) = (Integral M,(f | A)) + (Integral M,(f | B))
let S be SigmaField of X; for M being sigma_Measure of S
for f being PartFunc of X,REAL
for A, B being Element of S st ex E being Element of S st
( E = dom f & f is_measurable_on E ) & f is nonnegative & A misses B holds
Integral M,(f | (A \/ B)) = (Integral M,(f | A)) + (Integral M,(f | B))
let M be sigma_Measure of S; for f being PartFunc of X,REAL
for A, B being Element of S st ex E being Element of S st
( E = dom f & f is_measurable_on E ) & f is nonnegative & A misses B holds
Integral M,(f | (A \/ B)) = (Integral M,(f | A)) + (Integral M,(f | B))
let f be PartFunc of X,REAL ; for A, B being Element of S st ex E being Element of S st
( E = dom f & f is_measurable_on E ) & f is nonnegative & A misses B holds
Integral M,(f | (A \/ B)) = (Integral M,(f | A)) + (Integral M,(f | B))
let A, B be Element of S; ( ex E being Element of S st
( E = dom f & f is_measurable_on E ) & f is nonnegative & A misses B implies Integral M,(f | (A \/ B)) = (Integral M,(f | A)) + (Integral M,(f | B)) )
assume that
A1:
ex E being Element of S st
( E = dom f & f is_measurable_on E )
and
A2:
( f is nonnegative & A misses B )
; Integral M,(f | (A \/ B)) = (Integral M,(f | A)) + (Integral M,(f | B))
consider E being Element of S such that
A3:
E = dom f
and
A4:
f is_measurable_on E
by A1;
R_EAL f is_measurable_on E
by A4, Def6;
hence
Integral M,(f | (A \/ B)) = (Integral M,(f | A)) + (Integral M,(f | B))
by A2, A3, MESFUNC5:97; verum