let X be non empty set ; for S being SigmaField of X
for M being sigma_Measure of S
for f being PartFunc of X,ExtREAL
for A being Element of S st ex E being Element of S st
( E = dom f & f is_measurable_on E ) & f is nonnegative holds
0 <= Integral M,(f | A)
let S be SigmaField of X; for M being sigma_Measure of S
for f being PartFunc of X,ExtREAL
for A being Element of S st ex E being Element of S st
( E = dom f & f is_measurable_on E ) & f is nonnegative holds
0 <= Integral M,(f | A)
let M be sigma_Measure of S; for f being PartFunc of X,ExtREAL
for A being Element of S st ex E being Element of S st
( E = dom f & f is_measurable_on E ) & f is nonnegative holds
0 <= Integral M,(f | A)
let f be PartFunc of X,ExtREAL ; for A being Element of S st ex E being Element of S st
( E = dom f & f is_measurable_on E ) & f is nonnegative holds
0 <= Integral M,(f | A)
let A be Element of S; ( ex E being Element of S st
( E = dom f & f is_measurable_on E ) & f is nonnegative implies 0 <= Integral M,(f | A) )
assume that
A1:
ex E being Element of S st
( E = dom f & f is_measurable_on E )
and
A2:
f is nonnegative
; 0 <= Integral M,(f | A)
consider E being Element of S such that
A3:
E = dom f
and
A4:
f is_measurable_on E
by A1;
A5:
ex C being Element of S st
( C = dom (f | A) & f | A is_measurable_on C )
proof
take C =
E /\ A;
( C = dom (f | A) & f | A is_measurable_on C )
thus
dom (f | A) = C
by A3, RELAT_1:90;
f | A is_measurable_on C
A6:
C = (dom f) /\ C
by A3, XBOOLE_1:17, XBOOLE_1:28;
A7:
dom (f | A) =
C
by A3, RELAT_1:90
.=
dom (f | C)
by A6, RELAT_1:90
;
A8:
for
x being
set st
x in dom (f | A) holds
(f | A) . x = (f | C) . x
f is_measurable_on C
by A4, MESFUNC1:34, XBOOLE_1:17;
then
f | C is_measurable_on C
by A6, Th48;
hence
f | A is_measurable_on C
by A7, A8, FUNCT_1:9;
verum
end;
then
0 <= integral+ M,(f | A)
by A2, Th21, Th85;
hence
0 <= Integral M,(f | A)
by A2, A5, Th21, Th94; verum