let n be Element of NAT ; for K being Field
for A being Matrix of K st n > 0 & len A > 0 holds
(0. K,n,(len A)) * A = 0. K,n,(width A)
let K be Field; for A being Matrix of K st n > 0 & len A > 0 holds
(0. K,n,(len A)) * A = 0. K,n,(width A)
let A be Matrix of K; ( n > 0 & len A > 0 implies (0. K,n,(len A)) * A = 0. K,n,(width A) )
assume that
A1:
n > 0
and
A2:
len A > 0
; (0. K,n,(len A)) * A = 0. K,n,(width A)
A3:
len (0. K,n,(len A)) = n
by MATRIX_1:def 3;
then A4:
width (0. K,n,(len A)) = len A
by A1, MATRIX_1:20;
then A5:
len ((0. K,n,(len A)) * A) = n
by A3, MATRIX_3:def 4;
A6:
width ((0. K,n,(len A)) * A) = width A
by A4, MATRIX_3:def 4;
((0. K,n,(len A)) * A) + ((0. K,n,(len A)) * A) =
((0. K,n,(len A)) + (0. K,n,(len A))) * A
by A1, A2, A3, A4, MATRIX_4:63
.=
(0. K,n,(len A)) * A
by MATRIX_3:6
;
hence
(0. K,n,(len A)) * A = 0. K,n,(width A)
by A5, A6, MATRIX_4:6; verum