let D be non empty set ; for I, J being non empty set
for F, G being BinOp of D
for f being Function of I,D
for g being Function of J,D
for X being Element of Fin I
for Y being Element of Fin J st F is having_a_unity & F is commutative & F is associative & F is having_an_inverseOp & G is_distributive_wrt F & G is commutative holds
F $$ [:X,Y:],(G * f,g) = F $$ Y,(G [;] (F $$ X,f),g)
let I, J be non empty set ; for F, G being BinOp of D
for f being Function of I,D
for g being Function of J,D
for X being Element of Fin I
for Y being Element of Fin J st F is having_a_unity & F is commutative & F is associative & F is having_an_inverseOp & G is_distributive_wrt F & G is commutative holds
F $$ [:X,Y:],(G * f,g) = F $$ Y,(G [;] (F $$ X,f),g)
let F, G be BinOp of D; for f being Function of I,D
for g being Function of J,D
for X being Element of Fin I
for Y being Element of Fin J st F is having_a_unity & F is commutative & F is associative & F is having_an_inverseOp & G is_distributive_wrt F & G is commutative holds
F $$ [:X,Y:],(G * f,g) = F $$ Y,(G [;] (F $$ X,f),g)
let f be Function of I,D; for g being Function of J,D
for X being Element of Fin I
for Y being Element of Fin J st F is having_a_unity & F is commutative & F is associative & F is having_an_inverseOp & G is_distributive_wrt F & G is commutative holds
F $$ [:X,Y:],(G * f,g) = F $$ Y,(G [;] (F $$ X,f),g)
let g be Function of J,D; for X being Element of Fin I
for Y being Element of Fin J st F is having_a_unity & F is commutative & F is associative & F is having_an_inverseOp & G is_distributive_wrt F & G is commutative holds
F $$ [:X,Y:],(G * f,g) = F $$ Y,(G [;] (F $$ X,f),g)
let X be Element of Fin I; for Y being Element of Fin J st F is having_a_unity & F is commutative & F is associative & F is having_an_inverseOp & G is_distributive_wrt F & G is commutative holds
F $$ [:X,Y:],(G * f,g) = F $$ Y,(G [;] (F $$ X,f),g)
let Y be Element of Fin J; ( F is having_a_unity & F is commutative & F is associative & F is having_an_inverseOp & G is_distributive_wrt F & G is commutative implies F $$ [:X,Y:],(G * f,g) = F $$ Y,(G [;] (F $$ X,f),g) )
assume that
A1:
( F is having_a_unity & F is commutative & F is associative )
and
A2:
( F is having_an_inverseOp & G is_distributive_wrt F )
and
A3:
G is commutative
; F $$ [:X,Y:],(G * f,g) = F $$ Y,(G [;] (F $$ X,f),g)
thus F $$ [:X,Y:],(G * f,g) =
F $$ [:Y,X:],(G * g,f)
by A1, A3, Th25
.=
F $$ Y,(G [:] g,(F $$ X,f))
by A1, A2, Th28
.=
F $$ Y,(G [;] (F $$ X,f),g)
by A3, FUNCOP_1:79
; verum