let n be Element of NAT ; for K being Field
for A being Matrix of n,K holds
( A = 0. K,n iff for i, j being Element of NAT st 1 <= i & i <= n & 1 <= j & j <= n holds
A * i,j = 0. K )
let K be Field; for A being Matrix of n,K holds
( A = 0. K,n iff for i, j being Element of NAT st 1 <= i & i <= n & 1 <= j & j <= n holds
A * i,j = 0. K )
let A be Matrix of n,K; ( A = 0. K,n iff for i, j being Element of NAT st 1 <= i & i <= n & 1 <= j & j <= n holds
A * i,j = 0. K )
thus
( A = 0. K,n implies for i, j being Element of NAT st 1 <= i & i <= n & 1 <= j & j <= n holds
A * i,j = 0. K )
( ( for i, j being Element of NAT st 1 <= i & i <= n & 1 <= j & j <= n holds
A * i,j = 0. K ) implies A = 0. K,n )proof
set A2 =
0. K,
n;
set B2 =
0. K,
n;
reconsider B3 =
0. K,
n,
n as
Matrix of
n,
K ;
set A3 =
0. K,
n,
n;
assume A1:
A = 0. K,
n
;
for i, j being Element of NAT st 1 <= i & i <= n & 1 <= j & j <= n holds
A * i,j = 0. K
let i,
j be
Element of
NAT ;
( 1 <= i & i <= n & 1 <= j & j <= n implies A * i,j = 0. K )
assume
( 1
<= i &
i <= n & 1
<= j &
j <= n )
;
A * i,j = 0. K
then
[i,j] in Indices (0. K,n)
by MATRIX_1:38;
then
(
0. K,
n,
n = 0. K,
n &
((0. K,n) + (0. K,n)) * i,
j = ((0. K,n) * i,j) + ((0. K,n) * i,j) )
by MATRIX_3:def 1, MATRIX_3:def 3;
then
(0. K,n) * i,
j = ((0. K,n) * i,j) + ((0. K,n) * i,j)
by MATRIX_3:6;
then ((0. K,n) * i,j) - ((0. K,n) * i,j) =
((0. K,n) * i,j) + (((0. K,n) * i,j) - ((0. K,n) * i,j))
by RLVECT_1:42
.=
((0. K,n) * i,j) + (0. K)
by RLVECT_1:28
.=
(0. K,n) * i,
j
by RLVECT_1:10
;
hence
A * i,
j = 0. K
by A1, RLVECT_1:28;
verum
end;
A2:
len A = n
by MATRIX_1:25;
A3:
Indices A = [:(Seg n),(Seg n):]
by MATRIX_1:25;
A4:
width A = n
by MATRIX_1:25;
assume A5:
for i, j being Element of NAT st 1 <= i & i <= n & 1 <= j & j <= n holds
A * i,j = 0. K
; A = 0. K,n
for i, j being Nat st [i,j] in Indices A holds
A * i,j = (A * i,j) + (A * i,j)
proof
let i,
j be
Nat;
( [i,j] in Indices A implies A * i,j = (A * i,j) + (A * i,j) )
reconsider i0 =
i,
j0 =
j as
Element of
NAT by ORDINAL1:def 13;
assume A6:
[i,j] in Indices A
;
A * i,j = (A * i,j) + (A * i,j)
then
j in Seg n
by A4, ZFMISC_1:106;
then A7:
( 1
<= j &
j <= n )
by FINSEQ_1:3;
i in Seg n
by A3, A6, ZFMISC_1:106;
then
( 1
<= i &
i <= n )
by FINSEQ_1:3;
then
A * i0,
j0 = 0. K
by A5, A7;
hence
A * i,
j = (A * i,j) + (A * i,j)
by RLVECT_1:10;
verum
end;
then
A = A + A
by A2, MATRIX_3:def 3;
then
A = 0. K,(len A),(width A)
by MATRIX_4:6;
hence
A = 0. K,n
by A2, A4, MATRIX_3:def 1; verum