let l, n, k be Nat; for K being Field
for A being Matrix of n,K st l in dom (1. K,n) & k in dom (1. K,n) & n > 0 holds
A * (ICol (1. K,n),l,k) = ICol A,l,k
let K be Field; for A being Matrix of n,K st l in dom (1. K,n) & k in dom (1. K,n) & n > 0 holds
A * (ICol (1. K,n),l,k) = ICol A,l,k
let A be Matrix of n,K; ( l in dom (1. K,n) & k in dom (1. K,n) & n > 0 implies A * (ICol (1. K,n),l,k) = ICol A,l,k )
assume that
A1:
( l in dom (1. K,n) & k in dom (1. K,n) )
and
A2:
n > 0
; A * (ICol (1. K,n),l,k) = ICol A,l,k
A3:
len (1. K,n) = n
by MATRIX_1:25;
A4:
width (1. K,n) = n
by MATRIX_1:25;
then A5:
dom (1. K,n) = Seg (width (1. K,n))
by A3, FINSEQ_1:def 3;
A6:
width (A @ ) = n
by MATRIX_1:25;
A7:
( width (ILine (1. K,n),l,k) = width (1. K,n) & len (A @ ) = n )
by Th1, MATRIX_1:25;
A8:
len A = n
by MATRIX_1:25;
A9:
width A = n
by MATRIX_1:25;
then A10:
Seg (width A) = dom (1. K,n)
by A3, FINSEQ_1:def 3;
(ILine (A @ ),l,k) @ =
((ILine (1. K,n),l,k) * (A @ )) @
by A1, Th6
.=
((A @ ) @ ) * ((ILine (1. K,n),l,k) @ )
by A2, A4, A7, A6, MATRIX_3:24
.=
A * ((ILine (1. K,n),l,k) @ )
by A2, A8, A9, MATRIX_2:15
.=
A * ((ILine ((1. K,n) @ ),l,k) @ )
by MATRIX_6:10
.=
A * (ICol (1. K,n),l,k)
by A1, A2, A5, Th15
;
hence
A * (ICol (1. K,n),l,k) = ICol A,l,k
by A1, A2, A10, Th15; verum