thus
( f is_less_than g iff for x being Element of X
for y being Element of Y holds f . x,y <= g . x,y )
verumproof
hereby ( ( for x being Element of X
for y being Element of Y holds f . x,y <= g . x,y ) implies f is_less_than g )
assume A1:
f is_less_than g
;
for x being Element of X
for y being Element of Y holds f . x,y <= g . x,ythus
for
x being
Element of
X for
y being
Element of
Y holds
f . x,
y <= g . x,
y
verumproof
let x be
Element of
X;
for y being Element of Y holds f . x,y <= g . x,ylet y be
Element of
Y;
f . x,y <= g . x,y
(
dom f = [:X,Y:] &
[x,y] in [:X,Y:] )
by FUNCT_2:def 1;
hence
f . x,
y <= g . x,
y
by A1, FUZZY_1:def 2;
verum
end;
end;
assume A2:
for
x being
Element of
X for
y being
Element of
Y holds
f . x,
y <= g . x,
y
;
f is_less_than g
A3:
for
c being
set st
c in dom f holds
f . c <= g . c
dom g = [:X,Y:]
by FUNCT_2:def 1;
hence
f is_less_than g
by A3, FUZZY_1:def 2;
verum
end;