let T be non empty TopSpace; for x being Point of T
for y being Point of TopStruct(# the carrier of T,the topology of T #)
for A being set st x = y holds
( A is Basis of x iff A is Basis of y )
let x be Point of T; for y being Point of TopStruct(# the carrier of T,the topology of T #)
for A being set st x = y holds
( A is Basis of x iff A is Basis of y )
let y be Point of TopStruct(# the carrier of T,the topology of T #); for A being set st x = y holds
( A is Basis of x iff A is Basis of y )
let A be set ; ( x = y implies ( A is Basis of x iff A is Basis of y ) )
assume A1:
x = y
; ( A is Basis of x iff A is Basis of y )
thus
( A is Basis of x implies A is Basis of y )
( A is Basis of y implies A is Basis of x )proof
assume A2:
A is
Basis of
x
;
A is Basis of y
then reconsider A =
A as
Subset-Family of
TopStruct(# the
carrier of
T,the
topology of
T #) ;
A is
Basis of
y
proof
A c= the
topology of
TopStruct(# the
carrier of
T,the
topology of
T #)
by A2, TOPS_2:78;
then A10:
A is
open
by TOPS_2:78;
A is
y -quasi_basis
proof
thus
y in Intersect A
by A1, A2, YELLOW_8:def 2;
YELLOW_8:def 2 for b1 being Element of bool the carrier of TopStruct(# the carrier of T,the topology of T #) holds
( not b1 is open or not y in b1 or ex b2 being Element of bool the carrier of TopStruct(# the carrier of T,the topology of T #) st
( b2 in A & b2 c= b1 ) )
let S be
Subset of
TopStruct(# the
carrier of
T,the
topology of
T #);
( not S is open or not y in S or ex b1 being Element of bool the carrier of TopStruct(# the carrier of T,the topology of T #) st
( b1 in A & b1 c= S ) )
reconsider SS =
S as
Subset of
T ;
assume that A3:
S is
open
and A4:
y in S
;
ex b1 being Element of bool the carrier of TopStruct(# the carrier of T,the topology of T #) st
( b1 in A & b1 c= S )
SS is
open
by A3, PRE_TOPC:60;
then consider W being
Subset of
T such that A5:
(
W in A &
W c= SS )
by A1, A2, A4, YELLOW_8:def 2;
reconsider V =
W as
Subset of
TopStruct(# the
carrier of
T,the
topology of
T #) ;
take
V
;
( V in A & V c= S )
thus
(
V in A &
V c= S )
by A5;
verum
end;
hence
A is
Basis of
y
by A10;
verum
end;
hence
A is
Basis of
y
;
verum
end;
assume A6:
A is Basis of y
; A is Basis of x
then reconsider A = A as Subset-Family of T ;
A is Basis of x
hence
A is Basis of x
; verum