let f be FinSequence of (TOP-REAL 2); ( f is being_S-Seq implies for p being Point of (TOP-REAL 2) st p in L~ f & f . 1 in L~ (L_Cut f,p) holds
f . 1 = p )
assume A1:
f is being_S-Seq
; for p being Point of (TOP-REAL 2) st p in L~ f & f . 1 in L~ (L_Cut f,p) holds
f . 1 = p
then A2:
len f >= 2
by TOPREAL1:def 10;
A3:
len f in dom f
by A1, FINSEQ_5:6;
1 in dom f
by A1, FINSEQ_5:6;
then A4:
f /. 1 = f . 1
by PARTFUN1:def 8;
let p be Point of (TOP-REAL 2); ( p in L~ f & f . 1 in L~ (L_Cut f,p) implies f . 1 = p )
assume that
A5:
p in L~ f
and
A6:
f . 1 in L~ (L_Cut f,p)
and
A7:
f . 1 <> p
; contradiction
set g = mid f,((Index p,f) + 1),(len f);
A8:
not f . 1 in L~ (mid f,((Index p,f) + 1),(len f))
by A1, A5, Th9;
then
p <> f . ((Index p,f) + 1)
by A6, JORDAN3:def 4;
then A9:
L_Cut f,p = <*p*> ^ (mid f,((Index p,f) + 1),(len f))
by JORDAN3:def 4;
per cases
( mid f,((Index p,f) + 1),(len f) is empty or not mid f,((Index p,f) + 1),(len f) is empty )
;
suppose
not
mid f,
((Index p,f) + 1),
(len f) is
empty
;
contradictionthen
L~ (L_Cut f,p) = (LSeg p,((mid f,((Index p,f) + 1),(len f)) /. 1)) \/ (L~ (mid f,((Index p,f) + 1),(len f)))
by A9, SPPOL_2:20;
then A10:
f . 1
in LSeg p,
((mid f,((Index p,f) + 1),(len f)) /. 1)
by A6, A8, XBOOLE_0:def 3;
A11:
1
+ 1
<= len f
by A1, TOPREAL1:def 10;
then A12:
2
in dom f
by FINSEQ_3:27;
consider i being
Element of
NAT such that A13:
1
<= i
and A14:
i + 1
<= len (<*p*> ^ (mid f,((Index p,f) + 1),(len f)))
and A15:
f /. 1
in LSeg (<*p*> ^ (mid f,((Index p,f) + 1),(len f))),
i
by A6, A4, A9, SPPOL_2:13;
LSeg (<*p*> ^ (mid f,((Index p,f) + 1),(len f))),
i c= LSeg f,
(((Index p,f) + i) -' 1)
by A5, A13, A14, JORDAN3:49;
then A16:
((Index p,f) + i) -' 1
= 1
by A1, A2, A15, JORDAN5B:33;
A17:
1
<= Index p,
f
by A5, JORDAN3:41;
then
1
+ 1
<= (Index p,f) + i
by A13, XREAL_1:9;
then A18:
(Index p,f) + i = 1
+ 1
by A16, XREAL_1:237, XXREAL_0:2;
then
Index p,
f = 1
by A13, A17, Th10;
then
p in LSeg f,1
by A5, JORDAN3:42;
then A19:
p in LSeg (f /. 1),
(f /. (1 + 1))
by A11, TOPREAL1:def 5;
i = 1
by A13, A17, A18, Th10;
then
(mid f,((Index p,f) + 1),(len f)) /. 1
= f /. (1 + 1)
by A3, A18, A12, SPRECT_2:12;
hence
contradiction
by A7, A4, A10, A19, SPRECT_3:16;
verum end; end;