let A be closed-interval Subset of REAL ; for Z being open Subset of REAL st A c= Z holds
integral (sin + ((id Z) (#) cos )),A = (((id Z) (#) sin ) . (upper_bound A)) - (((id Z) (#) sin ) . (lower_bound A))
let Z be open Subset of REAL ; ( A c= Z implies integral (sin + ((id Z) (#) cos )),A = (((id Z) (#) sin ) . (upper_bound A)) - (((id Z) (#) sin ) . (lower_bound A)) )
assume A1:
A c= Z
; integral (sin + ((id Z) (#) cos )),A = (((id Z) (#) sin ) . (upper_bound A)) - (((id Z) (#) sin ) . (lower_bound A))
A2:
cos is_differentiable_on Z
by FDIFF_1:34, SIN_COS:72;
A3:
for x being Real st x in Z holds
(id Z) . x = (1 * x) + 0
by FUNCT_1:35;
dom (sin + ((id Z) (#) cos )) =
REAL /\ (dom ((id Z) (#) cos ))
by SIN_COS:27, VALUED_1:def 1
.=
dom ((id Z) (#) cos )
by XBOOLE_1:28
.=
(dom (id Z)) /\ REAL
by SIN_COS:27, VALUED_1:def 4
.=
dom (id Z)
by XBOOLE_1:28
;
then A4:
Z = dom (sin + ((id Z) (#) cos ))
by RELAT_1:71;
then
Z = (dom sin ) /\ (dom ((id Z) (#) cos ))
by VALUED_1:def 1;
then A5:
Z c= dom ((id Z) (#) cos )
by XBOOLE_1:18;
then
Z c= (dom (id Z)) /\ (dom cos )
by VALUED_1:def 4;
then
Z c= dom (id Z)
by XBOOLE_1:18;
then
id Z is_differentiable_on Z
by A3, FDIFF_1:31;
then
( sin is_differentiable_on Z & (id Z) (#) cos is_differentiable_on Z )
by A5, A2, FDIFF_1:29, FDIFF_1:34, SIN_COS:73;
then A6:
(sin + ((id Z) (#) cos )) | Z is continuous
by A4, FDIFF_1:26, FDIFF_1:33;
then
(sin + ((id Z) (#) cos )) | A is continuous
by A1, FCONT_1:17;
then A7:
sin + ((id Z) (#) cos ) is_integrable_on A
by A1, A4, INTEGRA5:11;
A8: dom ((id Z) (#) sin ) =
(dom (id Z)) /\ REAL
by SIN_COS:27, VALUED_1:def 4
.=
dom (id Z)
by XBOOLE_1:28
.=
Z
by RELAT_1:71
;
then A9:
(id Z) (#) sin is_differentiable_on Z
by FDIFF_4:45;
A10:
for x being Real st x in Z holds
(sin + ((id Z) (#) cos )) . x = (sin . x) + (x * (cos . x))
A12:
for x being Real st x in dom (((id Z) (#) sin ) `| Z) holds
(((id Z) (#) sin ) `| Z) . x = (sin + ((id Z) (#) cos )) . x
dom (((id Z) (#) sin ) `| Z) = dom (sin + ((id Z) (#) cos ))
by A4, A9, FDIFF_1:def 8;
then A14:
((id Z) (#) sin ) `| Z = sin + ((id Z) (#) cos )
by A12, PARTFUN1:34;
(sin + ((id Z) (#) cos )) | A is bounded
by A1, A4, A6, FCONT_1:17, INTEGRA5:10;
hence
integral (sin + ((id Z) (#) cos )),A = (((id Z) (#) sin ) . (upper_bound A)) - (((id Z) (#) sin ) . (lower_bound A))
by A1, A8, A7, A14, FDIFF_4:45, INTEGRA5:13; verum