let A be closed-interval Subset of REAL ; for D being Division of A holds Sum (upper_volume (chi A,A),D) = vol A
let D be Division of A; Sum (upper_volume (chi A,A),D) = vol A
A1:
for i being Nat st 1 <= i & i <= len (lower_volume (chi A,A),D) holds
(lower_volume (chi A,A),D) . i = (upper_volume (chi A,A),D) . i
proof
let i be
Nat;
( 1 <= i & i <= len (lower_volume (chi A,A),D) implies (lower_volume (chi A,A),D) . i = (upper_volume (chi A,A),D) . i )
assume that A2:
1
<= i
and A3:
i <= len (lower_volume (chi A,A),D)
;
(lower_volume (chi A,A),D) . i = (upper_volume (chi A,A),D) . i
i <= len D
by A3, Def8;
then A4:
i in dom D
by A2, FINSEQ_3:27;
then (lower_volume (chi A,A),D) . i =
vol (divset D,i)
by Th21
.=
(upper_volume (chi A,A),D) . i
by A4, Th22
;
hence
(lower_volume (chi A,A),D) . i = (upper_volume (chi A,A),D) . i
;
verum
end;
len (lower_volume (chi A,A),D) =
len D
by Def8
.=
len (upper_volume (chi A,A),D)
by Def7
;
then
lower_volume (chi A,A),D = upper_volume (chi A,A),D
by A1, FINSEQ_1:18;
hence
Sum (upper_volume (chi A,A),D) = vol A
by Th25; verum