let A be closed-interval Subset of REAL ; :: thesis: for Z being open Subset of REAL
for f being PartFunc of REAL ,REAL st A c= Z & ( for x being Real st x in Z holds
( 1 + (sin . x) <> 0 & 1 - (sin . x) <> 0 & f . x = 1 / (1 + (sin . x)) ) ) & dom (tan - sec ) = Z & Z = dom f & f | A is continuous holds
integral f,A = ((tan - sec ) . (sup A)) - ((tan - sec ) . (inf A))
let Z be open Subset of REAL ; :: thesis: for f being PartFunc of REAL ,REAL st A c= Z & ( for x being Real st x in Z holds
( 1 + (sin . x) <> 0 & 1 - (sin . x) <> 0 & f . x = 1 / (1 + (sin . x)) ) ) & dom (tan - sec ) = Z & Z = dom f & f | A is continuous holds
integral f,A = ((tan - sec ) . (sup A)) - ((tan - sec ) . (inf A))
let f be PartFunc of REAL ,REAL ; :: thesis: ( A c= Z & ( for x being Real st x in Z holds
( 1 + (sin . x) <> 0 & 1 - (sin . x) <> 0 & f . x = 1 / (1 + (sin . x)) ) ) & dom (tan - sec ) = Z & Z = dom f & f | A is continuous implies integral f,A = ((tan - sec ) . (sup A)) - ((tan - sec ) . (inf A)) )
assume that
A1: A c= Z and
A2: for x being Real st x in Z holds
( 1 + (sin . x) <> 0 & 1 - (sin . x) <> 0 & f . x = 1 / (1 + (sin . x)) ) and
A3: dom (tan - sec ) = Z and
A4: Z = dom f and
A5: f | A is continuous ; :: thesis: integral f,A = ((tan - sec ) . (sup A)) - ((tan - sec ) . (inf A))
A6: f is_integrable_on A by A1, A4, A5, INTEGRA5:11;
A7: for x being Real st x in Z holds
( 1 + (sin . x) <> 0 & 1 - (sin . x) <> 0 ) by A2;
then A8: tan - sec is_differentiable_on Z by A3, Th39;
A9: for x being Real st x in dom ((tan - sec ) `| Z) holds
((tan - sec ) `| Z) . x = f . x

proof

let x be Real; :: thesis: ( x in dom ((tan - sec ) `| Z) implies ((tan - sec ) `| Z) . x = f . x )
assume x in dom ((tan - sec ) `| Z) ; :: thesis: ((tan - sec ) `| Z) . x = f . x
then A10: x in Z by A8, FDIFF_1:def 8;
then ((tan - sec ) `| Z) . x = 1 / (1 + (sin . x)) by A3, A7, Th39
.= f . x by A2, A10 ;
hence ((tan - sec ) `| Z) . x = f . x ; :: thesis: verum

end;

dom ((tan - sec ) `| Z) = dom f by A4, A8, FDIFF_1:def 8;
then (tan - sec ) `| Z = f by A9, PARTFUN1:34;
hence integral f,A = ((tan - sec ) . (sup A)) - ((tan - sec ) . (inf A)) by A1, A4, A5, A6, A8, INTEGRA5:10, INTEGRA5:13; :: thesis: verum